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loris [4]
3 years ago
12

The proportion of adult women in a certain geographical region is approximately 49.49​%. A marketing survey telephones 100100 pe

ople at random. Complete parts a and b below. ​
a) What proportion of women in the sample of 100100 would you expect to​ see? . 49.49 ​(Type an integer or a​ decimal.) ​
b) How many​ women, on​ average, would you expect to find in a sample of that​ size? nothing women
Mathematics
1 answer:
Alinara [238K]3 years ago
8 0

Answer:

a) 49%

b) 49

Step-by-step explanation:

We have that:

The proportion of adult women in a certain geographical region is approximately 49%.

a) What proportion of women in the sample of 100100 would you expect to​ see?

The same as the region, that is 49%.

b) How many​ women, on​ average, would you expect to find in a sample of that​ size?

There are 100 people. In the region, the proportion of women is 49%.

So, in a sample of 100 people, you would expect to find 49 women.

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Answer:

3-Equalateral

Step-by-step explanation:

All the sides are all equal, which basically eliminates isosceles, isosceles acute, and scalene, therefore the answer is Equalateral.

5 0
3 years ago
Please help me solve this problem
Alex
The answer for this is X+2g= 0
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3 years ago
(-2) times (+5) times (-1) times (-5) times (-2)<br> please can u answer fast i have a test in 2 min
zlopas [31]

Answer:

100

Step-by-step explanation:

4 0
1 year ago
274,389,451,379 rounded to the nearest hundred​
Mama L [17]
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8 0
3 years ago
Find the work required to move an object in the force field F = e^x + y (1, 1, z) along the straight line from A(0, 0, 0) to B(-
DENIUS [597]

\vec F(x,y,z)=(e^x+y)(1,1,z)

is conservative if we can find a scalar function f such that \nabla f=\vec F. This would require

f_x=e^x+y

f_y=e^x+y

f_z=(e^x+y)z

Integrating both sides of the first equation wrt x gives

f(x,y,z)=e^x+xy+g(y,z)

Differentiating both sides of this wrt y gives

f_y=x+g_y=1\implies g_y=1-x\implies g(y,z)=y-xy+h(z)

but we assumed g was a function of y and z, independent of x. So there is no such f and \vec F is not conservative.

To find the work, first parameterize the path (call it C) by

\vec r(t)=(1-t)(0,0,0)+t(-4,5,-5)=(-4t,5t,-5t)

for 0\le t\le1. Then

\vec r'(t)=(-4,5,-5)

and the work is given by the line integral,

W=\displaystyle\int_C\vec F\cdot\mathrm d\vec r=\int_0^1(e^{-4t}+5t,e^{-4t}+5t,-(e^{-4t}+5t)5t)\cdot(-4,5,-5)\,\mathrm dt

W=\displaystyle\int_0^1(125t^2+5t+(25t+1)e^{-4t})\,\mathrm dt=\boxed{\frac{2207}{48}-\frac{129}{16e^4}}

8 0
3 years ago
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