Answer:
Q1. x= 18, y=59
Q2. m∠J= 56°
Step-by-step explanation:
Q1. (3x +5)°= y° (base ∠s of isos. △)
y= 3x +5 -----(1)
(3x +5)° +y° +(4x -10)°= 180° (∠ sum of △)
3x +5 +y +4x -10= 180
7x +y -5= 180
7x +y= 180 +5
7x +y= 185 -----(2)
Substitute (1) into (2):
7x +3x +5= 185
10x= 185 -5
10x= 180
x= 180 ÷10
x= 18
Substitute x= 18 into (1):
y= 3(18) +5
y= 59
Q2. (5x -13)°= (3x +17)° (base ∠s of isos. △)
5x -13= 3x +17
5x -3x= 17 +13
2x= 30
x= 30 ÷2
x= 15
∠LKJ
= 3(15) +17
= 62°
∠KLJ= 62° (base ∠s of isos. △)
m∠J
= 180° -62° -62° (∠ sum of △JKL)
= 56°
Hi There!
Dori leaves her house at 12pm.
50 steps per minute until 12:20pm.
Dori has a 20 minute advantage over Malory, find the amount of steps she is ahead by,
12 - 12:20pm. steps = 20 minutes = 20 x 50 = 1000 steps
Malory leaves her house at 12:20pm.
Walks 90 steps per minute.
12:20 - 12:30 pm. = 10 minutes = 10 x 90 = 900
Dori 12:20 - 12:30pm. = 10 minutes = 10 x 50 = 500
500 + 1000 = 1500
Mallory 12:30 - 12:40 = 10 minutes = 10 x 90 = 900
900 + 900 = 1800
Dori 12:30 - 12:45pm. = 15 minutes = 15 x 50 = 500
1750 + 500 = 2250
Mallory 12:40 - 12:45pm. = 5 minutes = 10 x 90 = 900
450 + 1800 = 2250
Answer: they have the same number steps at 12:45 p.m.
Hope This Helps :)
Answer:
3 apples = 885 calories
Step-by-step explanation:
3 x 285 = 885
Answer:
for 
Step-by-step explanation:
Given
-- First Term
--- half common difference
Required
Find the recursive rule
First, we calculate the common difference

Multiply through by 2


The second term of the sequence is:

The third term is:

So, we have:


Substitute f(1) for 3

Express 1 as 2 - 1

Substitute n for 2

Similarly:

Substitute f(2) for 11

Express 2 as 3 - 1

Substitute n for 3

Hence, the recursive is:
for 
Answer:
Confidence Interval is (21.76928571,23.43071429)
Step-by-step explanation:
The Formula we are going to use is:
±
Where:
μ is the mean of sample
σ is the standard deviation of population
n is the sample size
z is the distribution
In our case:
μ=$22.60,σ=$2.50
For 98% Confidence level, 1-α=98%
α=2%
α/2=1%=0.01
From Cumulative standardized Normal Distribution table
=2.326

P=23.430714 P=21.769286
Confidence Interval is (21.76928571,23.43071429)