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Contact [7]
3 years ago
11

Is 13/18 greater than 15/24

Mathematics
2 answers:
maks197457 [2]3 years ago
4 0

Answers:

Yes, 13/18 is greater than 15/24

Step-by-step explanation:

13/18 gives 0.72222222 while 15/24 gives 0.625. Hence, 0.72222 is greater (13/18).

svet-max [94.6K]3 years ago
3 0

Answer:

Yes it is

Step-by-step explanation:

The least common denominator between those two numbers is 72

13/18= 52/72

15/24=45/72

So 13/18 is greater.

One thing to keep in my mind, if the denominator is less, it is greater. Just watch out for the numerator because it may make it lower than the other fraction you are comparing.

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what is an equation of the line that is perpendicular to y=-4/5x+3 and passes through rhe point (4, 13)?
bezimeni [28]
If a line is perpendicular to another line, it has an opposite reciprocal slope. The opposite reciprocal of -4/5 is 5/4.

Based on the picture I drew, the y intercept is (0,3), so the equation should be y = 5/4 + 3.

6 0
3 years ago
Read 2 more answers
Kyle and Myles wanted to buy the soccer team food after the game.
iVinArrow [24]

Set up 2 equations:

Kyle: 5h + 3f = 14.50

Myles: 4h + 2f = 11.00

Lets get the two h's to cancel out.

Multiply Kyle by 4 and Myles by -5:

Kyle: 20h + 12f = 58

Myles: -20h - 10f = -55

Now add the two equations together:

2f = 3

Divide both sides by 2:

f = 3/2

f = 1.50

1 french fry cost $1.50

Now solve for the price of a hot dog:

5h + 3(1.50) = 14.50

5h + 4.50 = 14.50

Subtract 4.50 from both sides:

5h = 10.00

Divide both sides by 5:

h = 2

One hot dog cost $2.00

7 0
3 years ago
HELP PLS ASAP
8090 [49]

Answer:

D. x=(1/6)y^2

Step-by-step explanation:

D. x=(1/6)y^2

3 0
2 years ago
A family is relocating from St. Louis, Missouri, to California. Due to an increasing inventory of houses in St. Louis, it is tak
Naily [24]

The 99% Confidence interval for the mean sale time for all homes in the neighborhood is:87.857, 112.143.

<h3>Confidence interval</h3>

a. The assumption is: Assume that the population has a normal distribution.

The CI  is exact for the normal populations and for small samples the z-interval method should be used in a situation where the variable is normally distributed.

b. Confidence interval:

CI=Sample mean±z-score×Standard deviation/√Size of the sample

CI=100-2.576×20/√18, 100+2.576×20/√18

CI=100-12.143, 100+12.143

CI=87.857, 112.143

Therefore the 99% Confidence interval is 87.857, 112.143.

Learn more about Confidence interval here:brainly.com/question/15712887

#SPJ1

6 0
2 years ago
In a survey of a group of​ men, the heights in the​ 20-29 age group were normally​ distributed, with a mean of 67 inches and a s
liq [111]

Answer:

a) 20.33% probability that the participant is less than 64.5 inches.

b) 33.72% probability that the participant is more than 68.25 inches

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 67, \sigma = 3

a.) Find the probability that the participant is less than 64.5 inches?

This is the pvalue of Z when X = 64.5.

Z = \frac{X - \mu}{\sigma}

Z = \frac{64.5 - 67}{3}

Z = -0.83

Z = -0.83 has a pvalue of 0.2033

20.33% probability that the participant is less than 64.5 inches.

b.) Find the probability that the participant is more than 68.25 inches?

This is 1 subtracted by the pvalue of Z when X = 68.25.

Z = \frac{X - \mu}{\sigma}

Z = \frac{68.25 - 67}{3}

Z = 0.42

Z = 0.42 has a pvalue of 0.6628

1 - 0.6628 = 0.3372

33.72% probability that the participant is more than 68.25 inches

3 0
4 years ago
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