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Alex777 [14]
3 years ago
7

Jimmy borrowed $450 to start a lawn-mowing business. He charges $35 per lawn and it costs him $8 in operating costs per lawn.

Mathematics
1 answer:
Akimi4 [234]3 years ago
3 0

Answer: $450

Step-by-step explanation:

Given that:

Amount borrowed = $450

Amount charged per lawn = $35

Operating cost per lawn = $8

Jimmy's cost (C(x)) :

Amount borrowed + operating cost

If x lawns are mowed :

$450 + $8 per lawn

$450 + $8x

C(x) = 450 + 8x

Intercept (value of y when x = 0

Value of C(x) ; when x = 0

C(x) = 450 + 8(0)

C(x) = 450 + 0

C(x) = 450

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Suppose that 5 J of work is needed to stretch a spring from its natural length of 30 cm to a length of 39 cm.
vesna_86 [32]

Answer

given,

work = 5 J

spring stretch form 30 cm to 39 cm

W = \dfrac{1}{2}kx^2

x = 0.39 - 0.30 = 0.09 m

5 = \dfrac{1}{2}k\times 0.09^2

k = \dfrac{5\times 2}{0.09^2}

k = 1234.568 N/m

a) work when spring is stretched from  32 cm to 34 cm

x₂= 0.34 -0.30 = 0.04 m

x₁ = 0.32 - 0.30 = 0.02

W = \dfrac{1}{2}k(x_2^2-x_1^2)^2

W = \dfrac{1}{2}\times 1234.568 \times (0.04^2-0.02^2)^2

W = 0.741 J

b) F = k x

  25 = 1234.568 × x

     x = 0.0205 m

     x = 2.05 cm

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Step-by-step explanation:

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