Michael took the return trip at a velocity 33.75 miles per hour.
<h3>How fast did Michael drive in his return trip?</h3>
Let suppose that Michael drove in <em>straight line</em> road and at <em>constant</em> velocity. Therefore, the speed of the vehicle (v), in miles per hour, can be defined as distance traveled by the vehicle (d), in miles, divided by travel time (t), in hours.
First trip
45 = s / 3 (1)
Second trip
v = s / 4 (2)
By (1) and (2):
45 · 3 = 4 · v
v = 33.75 mi / h
Michael took the return trip at a velocity 33.75 miles per hour.
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Answer:3
If x=0 or x=1 it is trivial, so 0<x<1. Define a=1−x2, then 0<a<1.
Step-by-step explanation:
Answer:
Step-by-step explanation:
Alright, lets get started.
Lets find slope for both bikes one by one
For bike 1 :
There are two points on the graph of Bike 1, these two points are (2,3) and (4,6)
So the slope for bike 1 is : 
So the slope for bike 1 is : 
So the slope for bike 1 is : 
For bike 2 :
There are two points on the graph of Bike 2, these two points are (4,5) and (8,10)
So the slope for bike 2 is : 
So the slope for bike 2 is : 
Hence Bike 1 will win the race as slope of line bike1 is greater than slope of line bike 2. So, answer is option D
<span>A=30e^.198026t
= </span><span>30(e^.198026)^t
= 30(1.218994087)^t
approximately 21.90% every year
</span>
100 percent because 45 % is always in between 30 and 50 %