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Georgia [21]
3 years ago
11

An air traffic controller is tracking two planes. To start, Plan A is at an altitude of 2172 feet and Plan B is just taking off.

Plan A is gaining altitude at 35.25 feet per second and Plan B is gainnig altitude at 80.5 feet per second.
How many seconds will pass before the planes are at the same altitude?

What will their altitude be when they're at the same altitude?
Mathematics
1 answer:
azamat3 years ago
5 0

158.94 seconds

altitude is 12,794.61 feet

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Two hoses are filling a pool the first hose fills at a rate of x gallons per minute the second hose fills at a rate of 15 gallon
Zielflug [23.3K]

Answer:

B. (0, 5]∪(15,30] only (15,30] contains viable rates for the hoses.

Step-by-step explanation:

The question is incomplete. Find the complete question in the comment section.

For us to meet the pool maintenance company's schedule, the pool needs to fill at a combined

rate of at least 10 gallons per minute. If the inequality represents the combined rates of the hoses is 1/x+1/x-15≥10 we are to find all solutions to the inequality and identifies which interval(s) contain viable filling rates for the  hoses. On simplifying the equation;

\frac{1}{x} + \frac{1}{x-15} \geq \frac{1}{10}\\\\ find\ the \  LCM \ of \ the function \ on \ the \ LHS\\\\\frac{x-15+x}{x(x-15)} \geq \frac{1}{10}\\\\\frac{2x-15}{x(x-15)} \geq  \frac{1}{10}\\\\10(2x-15)\geq x(x-15)\\\\20x-150\geq x^2-15x\\\\collect \ like \ terms\\-x^2+20x+15x - 150\geq 0\\

-x^2+35x-150 \geq 0\\\\multipply \ through \ by \ minus\\x^2-35x+150 \leq  0\\\\(x^2-5x)-(30x+150) \leq  0\\\\x(x-5)-30(x-5) \leq 0\\\\

(x-5)(x-30) \leq 0\\\\x-5 \leq 0 and x - 30 \leq 0\\\\x \leq  5 \ and \ x \leq 30

The interval contains all viable rate are values of x that are less than 30. The range of interval is (0, 5]∪(15,30]. Since the pool needs to fill at a combined  rate of <em>at least 10 gallons per minute</em> for the pool to meet the company's schedule, <em>this means that the range of value of gallon must be more than 10, hence (15, 30] is the interval that contains the viable rates for the hoses.</em>

6 0
3 years ago
(−17)⋅(−6) −102 −23 23 102
Sladkaya [172]
The answer to your question is 102
6 0
3 years ago
What 3 numbers can you multiply to get 160?
timama [110]
Three numbers you can multiply to get 160. First, we make an equation.

Since 160 is divisible by 4, we will make the equation this.

(#1 * #2 * 4 = 160)
 Divide 160 by 4, and you get this. #1 * #2 = 40

Now, we divide 40 by 2. 

The final answer is 2, 20, and 4.

2x20x4= 160
3 0
4 years ago
Read 2 more answers
Solve for x, UV and TV​
stira [4]

We know that TV = TU + UV. Let's plug the values from the picture into our equation.

x + 25 = 9 + 2x + 28.

Let's combine like terms on the right side.

x + 25 = 2x + 37

Subtract 37 and x from both sides.

-12 = x

TV = x + 25 = -12 + 25 = 13

UV = 2x + 28 = 2(-12) + 28 = -24 + 28 = 4

8 0
3 years ago
Suppose that Sahil knows that 45 people with ages of 18 to 29 voted. Without using a calculator, he quickly says then 135 people
sergeinik [125]
His answer is correct because if you have the pie chart, it shows the percentage. <span>he did 45 times 3 to get the 135 because he though since 10% is 45 people he could multiply by 3 & get his answer. 
Hope this helped.</span>
4 0
3 years ago
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