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3 years ago

I need help on my math

Mathematics

2 answers:

Setler [38]3 years ago

8 0

Hey there so (-4)²=-4x-4=16

yuradex [85]3 years ago

6 0

$( - {4})^{2} = 16$

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Is y=150x proportional?

daser333 [38]

Answer:

yes

Step-by-step explanation:

A proportional equation is of the form

y = kx where k is the constant of proportionality

y = 150x is proportional

5 0

3 years ago

Read 2 more answers

Factor 12x6 - 27y4 completely

dlinn [17]

3(2x^3+3y^2) (2x^3 -3y^2)

7 0

2 years ago

You put $1200 in an account that earns 3% simple interest. Find the total amount in the account after 4 years (formula in pictur

Temka [501]

Using the equation i got
$1440

8 0

2 years ago

Write (8a-^3) -2/3 in simplest form

Anna71 [15]

$(8a^{-3})^{\frac{-2}{3}} = \frac{a^2}{4}$

Solution:

Given that,

$(8a^{-3})^{\frac{-2}{3}$

We have to write in simplest form

Use the following law of exponent

$(a^m)^n = a^{mn}$

Using this, simplify the given expression

$(8a^{-3})^{\frac{-2}{3}} = 8^{\frac{-2}{3}} \times a^{ -3 \times \frac{-2}{3}}\\\\Simplifying\ we\ get\\\\(8a^{-3})^{\frac{-2}{3}} = 8^{\frac{-2}{3}} \times a^2\\\\We\ know\ that\ 8 = 2^3\\\\Therefore\\\\(8a^{-3})^{\frac{-2}{3}} =2^3^{\frac{-2}{3}} \times a^2\\\\(8a^{-3})^{\frac{-2}{3}} =2^{-2} \times a^2\\\\(8a^{-3})^{\frac{-2}{3}} = \frac{a^2}{4}$

Thus the given expression is simplified

8 0

3 years ago

A standard deck has 52 cards consisting of 26 black and 26 red cards. Three cards are dealt from a shuffled deck without replace

Allisa [31]

They aren't independent since the probability uses all the cards in the deck

So at the first deal we have the chance of 26/52 of getting a red card, at the second deal we have the chance of a 25/51 of getting another red card, so they aren't independent

8 0

2 years ago