Its c2= a2+b2
the 2 is supposed to be squared
2(4z - 3 -1) = 166 - 46
2*(4z - 4) = 120
(4z - 4) = 120/2
4z - 4 = 60
4z = 60 + 4
4z = 64
z = 64/4
z = 16
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Find the general solution by separating the variables then integrating:
dy / dx = cosx℮^(y + sinx)
dy / dx = cosx℮ʸ℮^(sinx)
℮^(-y) dy = cosx℮^(sinx) dx
∫ ℮^(-y) dy = ∫ cosx℮^(sinx) dx
-℮^(-y) = ℮^(sinx) + C
℮^(-y) = C - ℮^(sinx)
-y = ln[C - ℮^(sinx)]
y = -ln[C - ℮^(sinx)]
Find the particular solution by solving for the constant:
When x = 0, y = 0
-ln(C - 1) = 0
ln(C - 1) = 0
C - 1 = 1
C = 2
<span>y = -ln[2 - ℮^(sinx)]
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Answer:
11
Step-by-step explanation:
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