Since you are given that the student registered early, the total number you deal with is all students who registered early.
211 + 329 = 540
number of undergraduates who registered early = 211
Among students who registered early:
p(undergraduate) = 211/540
Sample space is 36C4
Now, we want to know all of the combinations that have 1 digit in it.
So, we can have one here:
1XXX
X1XX
XX1X
XXX1
But we have 10 different digits to choose from. So, we need to introduce the combination term, nCr, where n is a list of all digits and r is how many we want.
Since we only want one, we will need 10C1 for the number of digits. But we need to choose three lowercases, so it becomes 10C1 × 26C3
Since it's a probability question, we need to divide that by our sample space, 36C4, and our percentage becomes 44%
Answer:
3 gray cats
Step-by-step explanation:
Write and solve an equation of ratios:
3 calico 1 gray
------------ = ------------
9 calico g
Cross multiplying, we get
3g = 9, or g = 3
They have 3 gray cats.
6 numbres
mean=(sum of all numbers)/(how many numbers)
mean=119
119=(102+122+106+113+107+x)/6
119=(550+x)/6
times 6 both sides
714=550+x
minus 550
164=x
your friend was asleep in clas and didn't pay attention
your frined was being funny (like some peple on this site)