Answer:
Step-by-step explanation:
log8 62 = x1
8^x1= 62
8^2 =64 >62 so <u>x1<2</u>
log7 50=x2
7^x2=50
7^2=49<50 so <u>x2>2</u>
we have, x1<2 and 2<x2
x1<2<x2
x1<x2
log8 62<log7 50
I think it's 42 since 7x6=42
20 is the answer to this problem
<span>LJK = KJM
-10x +3 = -x + 21
-10x + x = 21 - 3
-9x = 18
x = -2
KJM = -x + 21 = 2 + 21 = 23
LJM = LJK + KJM
LJM = 23 + 23
LJM = 46º..
i think thats how its done </span>
The answer is h = 2A/(b1 + b2).
In order to find this, use all the methods for solving typically used in these types of equations. See the below example.
A = 1/2(b1 + b2)h ---> Multiply both sides by 2.
2A = (b1 + b2)h -----> Divide both sides by (b1 + b2)
2A/(b1 + b2) = h
