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GaryK [48]
3 years ago
9

I don’t know how to do this question pls help

Mathematics
1 answer:
sineoko [7]3 years ago
5 0

Answer:

Step-by-step explanation:

Triangle P is mapped onto Q so P is the initial triangle that will transformed.

We can rotate counterclockwise 90° but we cannot do it about the origin (0,0) because the red point (5, 1) will end up at ( -1, 5) .

We see that the point (5, 1)  ends up at ( -2, 4) so the center of rotation is lower than the origin.

The transformation is rotation of 90° about the point (0,-1)

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Check all of the expressions that are equal to the one below.
Aloiza [94]
(7-11) • (5) = -20

A. (5) • 7 + (5) • (-11)
↳ 35 + (-55)
↳ 35 - 55 = -20

B. -(-7+11) • (5)
↳ -4 • 5 = -20

C. (5) • 7 - (5) • 11
↳ 35 - 55 = -20

D. (7+11) • (5)
↳ 18 • 5 = 90

A B & C are correct
4 0
3 years ago
Determine whether 96 is divisible by 3
aleksandr82 [10.1K]
96 divided by 3 is 32
Therefor, it is divisible by 3
Is this what you were looking for?
7 0
3 years ago
Read 2 more answers
What is the value of x in the equation in ( x + 6)- in (2x-1) =1
ki77a [65]

Answer:

x= -5

Step-by-step explanation:

5 0
3 years ago
Find the base of a parallelogram with the area of 60 in.² and height of 4 inches use the formula for the area of the parallelogr
Alexxx [7]
A = bh
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Hope this helped!
7 0
3 years ago
It is possible to get 2 solutions when the system of equations is: (check all that apply)
SVETLANKA909090 [29]

Answer:

A system of the equation of a circle and a linear equation

A system of the equation of a parabola and a linear equation

Step-by-step explanation:

Let us verify our answer

A system of the equation of a circle and a linear equation

Let an equation of a circle as x^2+ y^2 = 1 ..........(1)

Let a liner equation Y = x ............(2)

substitute (2) in (1)

x^2 + x^2 = 1\\2x^2 = 1\\

x^2 = \frac{1}{\sqrt{2} } \\x = +\frac{1}{\sqrt{2} } , -\frac{1}{\sqrt{2} }  so Y = +\frac{1}{\sqrt{2} } , -\frac{1}{\sqrt{2} }

so the two solution are ( (\frac{1}{\sqrt{2} } ,\frac{1}{\sqrt{2} }) (-\frac{1}{\sqrt{2} }, -\frac{1}{\sqrt{2} })

A system of the equation of a parabola and a linear equation

Let equation of Parabola be y^2 = x

and linear equation y = x

substitute

x^2 = x\\x^2 - x= 0\\x(x-1) = \\x = 0 , 1

Y = 0,1

so the two solutions will be (0,0) and (1,1)

3 0
3 years ago
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