Which equation represents the scentence.

Past experience has indicated that the breaking strength of yarn used in manufacturing drapery material is normally distributed

vlabodo [156]

Answer:

95% two-sided confidence interval on the true mean breaking strength is (94.8cm, 99.2cm)

Step-by-step explanation:

Our sample size is 11.

The first step to solve this problem is finding our degrees of freedom, that is, the sample size subtracted by 1. So

$df = 11-1 = 10$ .

Then, we need to subtract one by the confidence level $\alpha$ and divide by 2. So:

$\frac{1-0.95}{2} = \frac{0.05}{2} = 0.025$

Now, we need our answers from both steps above to find a value T in the t-distribution table. So, with 10 and 0.025 in the two-sided t-distribution table, we have $T = 1.812$

Now, we find the standard deviation of the sample. This is the division of the standard deviation by the square root of the sample size. So

$s = \frac{4}{\sqrt{11}} = 1.2060$

Now, we multiply T and s

$M = Ts = 1.812*1.2060 = 2.19/tex]For the lower end of the interval, we subtract the sample mean by M. So the lower end of the interval here is[tex]L = 97 - 2.19 = 94.81 = 94.8$ cm

For the upper end of the interval, we add the sample mean and M. So the upper end of the interval here is

$L = 97 + 2.19 = 99.19 = 99.2$ cm

So

95% two-sided confidence interval on the true mean breaking strength is (94.8cm, 99.2cm).

7 0

3 years ago

Find the volume of the region bounded above by the elliptical paraboloid zequals=9 minus 4 x squared minus 5 y squared9−4x2−5y2

Virty [35]

Answer:

$\int\limits^1_0 \int^1_0{z} \, dA$

Step-by-step explanation:

$\int\limits^1_0\int^1_0 {9-4x^2-5y^2dy} \, dx$

$\int\limits^1_0 {9y-4x^2y-\frac{5y^3}{3}|_0 ^1 } \, dx$

$\int\limits^1_0 {22/3 -4x^2} \, dx$

You finish the leftover.

7 0

3 years ago

Which trigonometric functions are negative in the fourth (IV) quadrant?

anzhelika [568]

<h3>Answers are: sine, tangent, cosecant, cotangent</h3>

Explanation:

On the unit circle we have some point (x,y) such that x = cos(theta) and y = sin(theta). The sine corresponds to the y coordinate of the point on the circle. Quadrant IV is below the x axis which explains why sine is negative here, since y < 0 here.

Since sine is negative, so is cosecant as this is the reciprocal of sine

csc = 1/sin

In quadrant IV, cosine is positive as x > 0 here. So the ratio tan = sin/cos is going to be negative. We have a negative over a positive when we divide.

Because tangent is negative, so is cotangent.

The only positive functions in Q4 are cosine and secant, which is because sec = 1/cos.

7 0

2 years ago

Solve the inequality 7y-34 ≤ 8

Vlad1618 [11]

Answer:

Explanation: start by adding 34 to both sides to make the variable stand alone giving you
7y is greater than or equal to 42
Then divide 7 into both sides to give you the answer of
Y=6

8 0

2 years ago

Height-9ft<br> Width-25ft<br> Volume-7650<br> Length-?

Licemer1 [7]

Step-by-step explanation:

V = h × w × l

7650 = 9 × 25 × l

So,

l = 7650 ÷ 9 ÷ 25

l = 850 ÷ 25

l = 34

For the final, the length is 34.

4 0

2 years ago