Largest integer: 57
x + x + 1 + x + 2 = 168
3x + 3 = 168
-3 -3
3x = 165
/3 /3
x = 55
x = smallest integer = 55
x + 1 = middle integer = 55 + 1 = 56
x + 2 = largest integer = 55 + 2 = 57
point slope form:y-2=4(x+1)
then distribute 4 and simplify y-2=4x+4 , y=4x+6 is the slope -y intercept form
then, move 4x on the left side, you get -4x+y=6 , multiply every term by -1, you get 4x-y=-6 which is standard form.
Answer: possible values of Range will be values that are >=91 or <=998
Step-by-step explanation:
Given that :
Set Q contains 20 positive integer values. The smallest value in Set Q is a single digit value and the largest value in Set Q is a three digit value.
Therefore,
given that the smallest value in set Q is a one digit number :
Then lower unit = 1, upper unit = 9( this represents the lowest and highest one digit number)
Also, the largest value in Set Q is a three digit value:
Then lower unit = 100, upper unit = 999 ( this represents the lowest and highest 3 digit numbers).
Therefore, the possible values of the range in SET Q:
The maximum possible range of the values in set Q = (Highest possible three digit value - lowest possible one digit) = (999 - 1) = 998
The least possible range of values in set Q = (lowest possible three digit value - highest possible one digit value) = (100 - 9) = 91
<h3>
Answer: 8</h3>
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Work Shown:
Let's say there are 28 cards in a full stack.
6/7 = 24/28 after multiplying top and bottom by 4
Since he has 24/28 of a stack left, this means he has 24 cards left.
He wants to arrange the remaining cards into piles so that each pile consists of 3/28 of a full stack. In other words, he wants each pile to have 3 cards.
So this must mean he will get 24/3 = 8 piles
(8 piles)*(3 cards per pile) = 8*3 = 24 cards total
Answer:
The answer is D
Step-by-step explanation:
You use base times height
1/2bh
=1/2(2x+5)(4x)
