Help my places immediately

Help can someone check

Serjik [45]

The answer is A because if you multiply you’ll get 70°

6 0

2 years ago

Why does 1.5 x 4.2 equal 6.3? Someone answer please

miskamm [114]

Answer: Look at it this way, you are adding 4.2, .5 times. So if you find what 1.5 is of 4.2 you then add that to 4.2. The 1 stands for how many times the number is being multiplied by. So in this case the number is only being multiplied once. Then we move onto the decimal point which says that the number is being multiplied by .5 times. This means that 2.1 (which is half of 4.2) is being added onto 4.2. Hope this makes sense. I always use a calculator for multiplying so its hard to put the process into words haha.

Step-by-step explanation:

3 0

1 year ago

6. You've just received an order of silk flower arrangements from your wholesaler. You paid $20.00 each for them. Your store use

cupoosta [38]

10% of $20 is $2 (take off the end 0)
$20+10%=?
$20+$2[this is 10%]=$22
The selling price is $22

7 0

2 years ago

What value of x makes the equation ×/7 - 5 = ×/2 + 4 true?

Pepsi [2]

X = -126/5 or -25.2 or -25 1/5

3 0

3 years ago

A traffic light at a certain intersection is green 50% of the time, yellow 10% of the time, and red 40% of the time. A car appro

kati45 [8]

Answer:

$6.4\times 10^{-5} = 0.000064 = 0.0064\%$ .

Step-by-step explanation:

Probability that the car encounters a green light on the first day: $50 \% = 0.5$ .

To meet the question's conditions, the car needs to encounter another green light on the second day. Given that the colors of the light on each day are "independent," the chance that there's a green light followed by another green light will be

$(0.5) \times 0.5 = 0.25$ .

Condition is met on the first two days and green light on the third day: $(0.5 \times 0.5) \times 0.5 = 0.125$ .
Condition is met on the first three days and green light on the fourth day: $(0.5 \times 0.5 \times 0.5) \times 0.5$ .

To meet the condition on the fifth day, there needs to be a yellow light. The probability that the condition is met on the first four days and on the fifth day will be $(0.5 \times 0.5 \times 0.5 \times 0.5) \times 0.1 = 0.5^{4} \times 0.1$ .

To meet the condition on the sixth day, all prior days should meet the conditions. Besides, there needs to be a red light on the sixth day. $(0.5^{4} \times 0.1) \times 0.4$

Seventh day: $(0.5^{4} \times 0.1 \times 0.4 ) \times 0.4$
Eighth day: $(0.5^{4} \times 0.1 \times 0.4^2 ) \times 0.4$
Ninth day: $(0.5^{4} \times 0.1 \times 0.4^3 ) \times 0.4$
Tenth day: $(0.5^{4} \times 0.1 \times 0.4^4 ) \times 0.4 = 0.5^{4} \times 0.1 \times 0.4^{5}$

The question asks that the condition be met on all ten days. As a result, the probability of meeting the condition will be equal to the probability on the tenth day: $0.5^{4} \times 0.1 \times 0.4^{5} = 6.4\times 10^{-5} = 0.000064 = 0.0064\%$ .

6 0

3 years ago

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