This is a little difficult for me! Can someone explain?
1 answer:
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Answer:
The 90% confidence interval for the mean score of all takers of this test is between 59.92 and 64.08. The lower end is 59.92, and the upper end is 64.08.
Step-by-step explanation:
We have that to find our level, that is the subtraction of 1 by the confidence interval divided by 2. So:
Now, we have to find z in the Ztable as such z has a pvalue of .
So it is z with a pvalue of , so
Now, find the margin of error M as such
In which is the standard deviation of the population and n is the size of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 62 - 2.08 = 59.92
The upper end of the interval is the sample mean added to M. So it is 62 + 2.08 = 64.08.
The 90% confidence interval for the mean score of all takers of this test is between 59.92 and 64.08. The lower end is 59.92, and the upper end is 64.08.
Answer:
(a) and (b) are not equivalent
(c) is equivalent
Step-by-step explanation:
Given
Required
Determine an equivalent or nonequivalent expression
We have:
Apply law of indices
<em>This is not equivalent to </em><em></em>
We have:
Apply law of indices
<em>This is not equivalent to </em><em></em>
<em></em>
<em /><em />
We have:
<em /><em />
Apply law of indices
<em /><em />
<em /><em />
<em>Evaluate the numerator</em>
<em /><em />
<em />
<em>This is an equivalent expression</em>