Answer:
<em>The order of subtraction is not important in any of the coordinates</em>
Step-by-step explanation:
Distance Between Two Points
Given two points (x1,y2) (x2,y2), the distance between them is given by the formula

The difference between both coordinates is squared, then added, and finally extracted the square root.
Based on the principle that

and also

We can notice it doesn't matter the sign of a the square of a is always positive. If we had subtracted in the opposite way, the distance would have resulted in exactly the same. In other words, the above formula is exactly the same as

As seen, it applies for both coordinates
The given equation of the ellipse is x^2
+ y^2 = 2 x + 2 y
At tangent line, the point is horizontal with the x-axis
therefore slope = dy / dx = 0
<span>So we have to take the 1st derivative of the equation
then equate dy / dx to zero.</span>
x^2 + y^2 = 2 x + 2 y
x^2 – 2 x = 2 y – y^2
(2x – 2) dx = (2 – 2y) dy
(2x – 2) / (2 – 2y) = 0
2x – 2 = 0
x = 1
To find for y, we go back to the original equation then substitute
the value of x.
x^2 + y^2 = 2 x + 2 y
1^2 + y^2 = 2 * 1 + 2 y
y^2 – 2y + 1 – 2 = 0
y^2 – 2y – 1 = 0
Finding the roots using the quadratic formula:
y = [-(- 2) ± sqrt ( (-2)^2 – 4*1*-1)] / 2*1
y = 1 ± 2.828
y = -1.828 , 3.828
<span>Therefore the tangents are parallel to the x-axis at points (1, -1.828)
and (1, 3.828).</span>
C i think if I’m not mistaken
Answer:
7 and 5
Step-by-step explanation:
7+5=12 and 7-5=2