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3 years ago

Simplify (4x3+ 13x − 7) − (6x2+ 9x + 2). −2x2+ 4x − 9 −2x2+ 22x − 5 4x3− 6x2+ 4x − 9 4x3− 6x2+ 22x − 5

1 answer:

kondor19780726 [428]3 years ago

4 0

(4x³+ 13x − 7) − (6x²<span>+ 9x + 2)
Remember that if they don't have the same exponents/bases (x</span>²,x³, etc.), then they cannot be grouped together.

This means that 4x³ and 6x² will be left alone because there are no other x² or x³ in the expression.

So first thing you do is distribute. Don't forget about that - in front of the second parentheses.
(4x³+ 13x − 7) − (6x²+ 9x + 2)
(4x³ + 13x − 7) + (−6x² - 9x - 2)
4x³ - 6x² + (13x - 7) + (-9x - 2)
4x³ - 6x² + 4x (- 7) + (- 2)
4x³ - 6x² + 4x - 9

So the answer is:
C. <span>4x3− 6x2+ 4x − 9</span>

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