Answer:
This is the location where a document or a portion of another document was retrieved. reference: computerhope.com
Answer:
if its a test try to just do it on your own ,you got nothing to lose from a test, its just to understand what you know on the concepts, but if you would still like answers just search around the net or here and you can always post the questions to ask people for help someone would eventually answer your questions but then beware of bots that post links as answer!
Explanation:
Answer:
The Datalink layer encapsulates each packet in a frame which contains the hardware address (MAC) of the source and destination computer (host) and the LLC information which identifies to which protocol in the prevoius layer (Network layer) the packet should be passed when it arrives to its destination.
Explanation:
Answer:
<em>Whole Numbers:</em>
0000 0001 (Binary) --> 1 (Decimal)
<em>Real Numbers:</em>
0000 0001 (Binary) --> 0.00390635 (Decimal)
Explanation:
In general, the smallest nonzero number that can be displayed in binary that is a whole number is 1. Consider that as you increase by 1 in the binary system starting from 0, you will have the following:
0000 0000 == 0
0000 0001 == 1 (Smallest nonzero)
0000 0010 == 2
0000 0011 == 3
... etc.
Notice the smallest value here is decimal 1. With this in mind, you will need to "program" you Flippy Do Pro to display this value. Alternatively, if you consider decimal numbers in binary with the Flippy Do Pro, you can have even smaller nonzero numbers. Depending on where you decide to place the decimal, you can even have smaller nonzero values.
Let's assume that you say this is a fractional representation of binary on the Flippy Do Pro. Then, you will say your decimal is infront of the display of the Flippy Do Pro, hence index 9 (which is not displayed). From here, you will simply say the following:
0000 0000 == 0.0
0000 0001 == 0.00390635 (Smallest nonzero)
0000 0010 == 0.0078125
0000 0100 == 0.015625
... etc.
Note, in binary, as you move the value of 1 to the right of the decimal, you are doing (1 / 2^n), where n is the index value to the right of the decimal.
Hence, depending on if you are to consider just whole numbers or real numbers, the smallest value displayed can be different even though the number being displayed is still 0000 0001.
Cheers.
Answer:
Contact me if you need additional comment/explanation:
1. Human-language declarations for x and n:
let x be the number of iterations that have been examined at a given time. let n be the multiple iterations upon which your code will execute.
2. What we're doing:
The first code block (Block A) uses only one variable, x (defined above), and uses 5 (an integer) rather than the variable n (defined above).
The second code block (Block B) uses both of the variables (x and n) that are defined above. The integer, 5, will be replaced by the variable, n. So, Block B literally performs an action at each nth iteration.
Our goal is to do something every Xth iteration and every 5th/nth iteration. We are going through 100 iterations.
m. Easy-to-understand code:
Block A, minimal variables:
Explanation:
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