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stich3 [128]
3 years ago
5

Which pair of ratios does

Mathematics
2 answers:
grandymaker [24]3 years ago
5 0

Answer:

8:14

Step-by-step explanation:

just multiply

earnstyle [38]3 years ago
4 0
A)8:14 and 20:35 :3 xd
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PLEASE HELP ME ASAP!!!
blsea [12.9K]

Answer:

Step-by-step explanation:

When equal bases are multiplied, the powers add.

The bases of both expressions is x.

The powers are 5 and 7.

The answer is x^(5 + 7) = x^(12)

6 0
3 years ago
Which statement is used to prove that quadrilateral abcd is a parallelogram
gizmo_the_mogwai [7]

Answer:

Opposite sides must be congruent.

Step-by-step explanation:

Given is a picture of a quadrilateal ABCD

We have to prove that this is a parallelogram.

Recall the properties of parallelogram as

i) diagonals bisect each other

ii) opposite sides parallel

iii) opposite sides congruent

or iv) one pair of opposite sides equal and parallel

We have hence to get opposite sides congruent

So last option is right

5 0
3 years ago
Solve a math problem
mars1129 [50]
1000add10000. 11000............
7 0
4 years ago
Read 2 more answers
kayden is given this question 42000 x 3000 give your answer in standard form his answer is 12.6 x 10^7 is kayden correct explain
boyakko [2]

Answer:

Step-by-step explanation:

No, Kayden is not correct.

Without even making any calculations, we can evaluate his answer.

When writing standard form, the decimal point should be before the second non-zero number.

While we do not say the answer to the multiplication given is not correct, the expression for the standard form is not

I

7 0
3 years ago
Remember to show work and explain. Use the math font.
vichka [17]

Answer:

\large\boxed{1.\ f^{-1}(x)=\sqrt[12]{3^x}}\\\\\boxed{2.\ f^{-1}(x)=\sqrt[4]{3^x}}\\\\\ \boxed{3.\ f^{-1}(x)=\sqrt[3]{4^{7-x}}}

Step-by-step explanation:

(a^n)^m=a^{nm}\\\\\log_ab=c\iff a^c=b\\\\a^{\log_ax}=x\\\\n\log_ab=\log_ab^n\\\\\log_ab+\log_ac=\log_a(bc)\\============================\\\\1.\\y=3\log_3x^4\to y=\log_3(x^4)^3\to y=\log_3x^{12}

2.\\y=\log_3x^4\\\\\text{Exchange x and y. Solve for y:}\\\\\log_3y^4=x\Rightarrow3^{\log_3y^4}=3^x\Rightarrow y^{4}=3^x\\\\y=\sqrt[4]{3^x}\\-------------------------

3.\\y=-\log_4x^3+7\\\\\text{Exchange x and y. Solve for y:}\\\\-\log_4y^3+7=x\qquad\text{subtract 7 from both sides}\\\\-\log_4 y^3=x-7\qquad\text{change the signs}\\\\\log_4y^3=7-x\Rightarrow4^{\log_4y^3}=4^{7-x}\\\\y^3=4^{7-x}\Rightarrow y=\sqrt[3]{4^{7-x}}

7 0
3 years ago
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