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Ulleksa [173]
3 years ago
6

Can someone tell me the answers This is math by the way

Mathematics
1 answer:
stellarik [79]3 years ago
6 0

Answer:

x>1/2

Step-by-step explanation:

2x+1−8x<8x−2−8x

−6x+1<−2

−6x+1−1<−2−1

−6x /−6 <

−3 /−6

x>1/2

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Two cylindrical science beakers are similar. The smaller beaker has a radius of 2 centimeters and a height of 4 centimeters. Its
salantis [7]

Answer:

itsa 1200 B

Step-by-step explanation:

6 0
3 years ago
use the graph that shows the averge number of the heartbeats for an active adult brown bear and hibernating brown bear
julia-pushkina [17]
<span>Given the graph that shows the average number of the heartbeats for an active adult brown bear and hibernating brown bear

Part a</span>.
What does the point (2, 120) represent on the graph?

From the graph the x axis represent the time in minutes while the y axis represent the number of heartbeats.

Therefore, point (2, 120) means that it takes an active adult brown bear an average of 2 minutes to have 120 heartbeat.


Part b.
What does the ratio of the y-coordinate to the x-coordinate for each pair of points on the graph represent?

From the graph the x axis represent the time in minutes while the y axis represent the number of heartbeats.

Therefore, the ratio of the y-coordinate to the x-coordinate for each pair of points on the graph represents the average number of heatbeats of an active brown dear and a hibernating brown dear per minute.


Part c.
Use the graph to find the bear’s average heart rate when it is active and when it is hibernating.

The bear's average heart rate is given by the ratio of the y-coordinate to the x-coordinate for each pair of points on the graph.

This can be obtained by taking any two points from the graph and taking the slope.

Recall that the slope of a line is given by
m= \frac{y_2-y_1}{x_2-x_1}

For the average hearbeat of an active brown bear, using the points (1.5, 90) and (2, 120), we calculate the average heat rate as follows:
Average heart rate = \frac{120-90}{2-1.5} = \frac{30}{0.5} =60 \ beats \ per \ minute

Also, for the average hearbeat of a hibernating brown bear, using the points (1.5, 18) and (2, 24), we calculate the average heat rate as follows:
Average heart rate = \frac{24-18}{2-1.5} = \frac{6}{0.5} =12 \ beats \ per \ minute
4 0
4 years ago
Help me and thx alot
Svet_ta [14]

Answer:

easyyyyyyy

Step-by-step explanation:

table J!

8 0
3 years ago
dawn and pablo are members of a normally distributed population that is being sampled. if the chance of dawn being included in t
pav-90 [236]
Pablo must have the same chance as Dawn of being included in the sample, in order for valid inferences to be made based on the sample.
Therefore the chance of Pablo being included in the sample must be 0.05%.
4 0
3 years ago
Read 2 more answers
Which does not represent the problem Shonne? Bethany has 1 3/8 yards of orange fabric. She uses 2/3 of the fabric to make a tote
White raven [17]

Answer:

Step-by-step explanation:

Total yard of fabric = 1 3/8 = 11/8yd

Fabric used for tote bag is 2/3 of 11/8

= 2/3 × 11/8

= 11/12 yards

6 0
3 years ago
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