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Alla [95]
3 years ago
13

If a 1 could 1 could a 1 sit on a 2 when a 2 eats a 3 after the 3 sits on 1?

Mathematics
1 answer:
jok3333 [9.3K]3 years ago
7 0

Answer:

no, 2 would be sitting on 1

Step-by-step explanation:

Download docx
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What are the steps to solve for: 1/5(x+5)=1/4(x-3)+1
andrew11 [14]
Step 1. Simplify \frac{1}{5} (x+5) to \frac{x+5}{5}

\frac{x+5}{5} = \frac{1}{4} (x-3)+1

Step 2. Simplify \frac{x+5}{5} to 1+ \frac{x}{5}

1+ \frac{x}{5} = \frac{1}{4} (x-3)+1

Step 3. Simplify \frac{1}{4} (x-3) to \frac{x-3}{4}

1+ \frac{x}{5} = \frac{x-3}{4} +1

Step 4. Cancel 1 on both sides

\frac{x}{5} = \frac{x-3}{4}

Step 5. Multiply both sides by 20 (the LCM of 5,4)

4x=5(x-3)

Step 6. Expand

4x=5x-15

Step 7. Subtract 5x from both sides

4x-5x=-15

Step 8. Simplify 4x-5x to -x

-x=-15

Step 9. Multiply both sides by -1

x=15

Done! :) Hope this helps! :)








3 0
3 years ago
Rewrite 5 3/7 as an improper fraction.
bija089 [108]
The answer should be 38/7
7 0
3 years ago
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Find the value of x and the value of y for which (x,23) and (18,y) ate the points on the graph y=0.5x+15
shutvik [7]

Answer:

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Step-by-step explanation:

for (x,23), 23=0.5x+15

x=16

for (18xy), y=0.5*18+15=24

8 0
3 years ago
2/10times6/10. Please help
babunello [35]

Answer:

I believe the answer is 1 2/10

Hope this helps!



8 0
3 years ago
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vfiekz [6]
Whatever the number of times you flip the disc, as long as the disc has uniformly distributed mass throughout the body, then

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7 0
3 years ago
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