All categories

3 years ago

If a 1 could 1 could a 1 sit on a 2 when a 2 eats a 3 after the 3 sits on 1?

Mathematics

1 answer:

jok3333 [9.3K]3 years ago

7 0

Answer:

no, 2 would be sitting on 1

Step-by-step explanation:

Download docx

You might be interested in

The length of a swimming pool is 3 feet longer than it’s width. The swimming pool is surrounded by a deck that is 2 feet wide an

Firlakuza [10]

Answer:

The Length of swimming pool is 8.35 feet

The width of swimming pool is 5.35 feet

Step-by-step explanation:

Given as :

The length of swimming pool is 3 feet longer that its width

Let The width of swimming pool = w feet

So, The Length of swimming pool = L = (w + 3) feet

Now, The swimming pool is surrounded by deck of 2 feet wide

The width of deck = w' = w + 2 + 2 = (w + 4) feet

The area of deck = 116 feet²

The length of deck = L' = L + 2 + 2 = (L + 4) feet

So, L' = (w + 3 + 4) feet

I.e L' = (w + 7) feet

∵ The area of deck = 116 feet²

So , L' × w' = 116 feet²

(w + 7)× (w + 4) = 116

Or, w² + 4 w + 7 w + 28 = 116

Or, w² + 11 w - 88 = 0

Solving the quadratic equation as

ax² + bx + c = 0

So, w = $\dfrac{-b\pm \sqrt{b^{2}-4\times a\times c}}{2\times a}$

Or, w = $\dfrac{-11\pm \sqrt{11^{2}-4\times 1\times (-88)}}{2\times 1}$

Or, w = $\dfrac{-11\pm \sqrt{473}}{2}$

or, w = $\dfrac{-11\pm 21.7}{2}$

or, w = 5.35 , -16.35

The width of swimming pool = w = 5.35 feet

The Length of swimming pool = L = (5.35 + 3) feet = 8.35 feet

Hence, The Length of swimming pool is 8.35 feet

And The width of swimming pool is 5.35 feet

Answer

3 0

3 years ago

HELP ASAP The graph shows the relationship between time, in hours, and the population, in thousands of a culture of bacteria. y

Harrizon [31]

Answer:

I’m doing that exact question right now on a test so I just guessed

Step-by-step explanation:

3 0

3 years ago

Carolina is mowing lawns for a summer job. For every mowing job, she charges an initial fee plus $6 sign, for each hour of work.

Shkiper50 [21]

ya the answ is good to hear ok bye t

8 0

3 years ago

Read 2 more answers

Find value of a cone

tino4ka555 [31]

The answer is 3.14.

4 0

3 years ago

Determine the maximum value of the objective function, P.

Ad libitum [116K]

Answer:

Maximum (250,125) Answer

Step-by-step explanation:

This is more of a graphing problem than it is anything else.

Begin by graphing all 4 given equations.

When you do that, mark the intersection points of at least 2 lines. In this case it is exactly 2 lines for each intersecting point.

6x + 4y <= 2000 and 2x + 4y <= 1000 intersect at (250,125)

x=>0 and y=>0 intersect at (0,0)

6x + 4y <=2000 and x => 0 intersect at 333.333

2x + 4y <=1000 and y>=0 intersect at 0,250.

Any other intersection points fall outside the range of the givens. The shaded part we are interested in is sort of a very dark green/blue. It is the interior of the quadrilateral determined by the 4 vertices that are marked.

Now all you have to do is determine the maximum point using P=15x + 12y

For 0,0 P = 15*0 + 12,0 = 0

For 0,250 P = 15*0 + 12*250 = 3000

For 333.3333,0 P = 15*333.3333 + 12*0 = 5000 rounded.

For 250,125 P = 15*250 + 12*125 = 5250 Which is the maximum

Answer (250,125) produces the maximum value Answer

5 0

3 years ago