Answer:
1. A
2. D
3. C
4. E
5. B
Step-by-step explanation:
Check the picture below.

since the distance AB cannot be a negative value, thus is not -3-√(130).
For line B to AC: y - 6 = (1/3)(x - 4); y - 6 = (x/3) - (4/3); 3y - 18 = x - 4, so 3y - x = 14
For line A to BC: y - 6 = (-1)(x - 0); y - 6 = -x, so y + x = 6
Since these lines intersect at one point (the orthocenter), we can use simultaneous equations to solve for x and/or y:
(3y - x = 14) + (y + x = 6) => 4y = 20, y = +5; Substitute this into y + x = 6: 5 + x = 6, x = +1
<span>So the orthocenter is at coordinates (1,5), and the slopes of all three orthocenter lines are above.</span>
(6, 2 )
substitute x = 5 into the equation and solve for y
6y + 8 = 20 ( subtract 8 from both sides )
6y = 12 ( divide both sides by 6 )
y =
= 2
the ordered pair is (5, 2 )
Answer:
36:39
= 36/39 (divide by 3)
= 12/13
= <u>12:13 (option C)</u>