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ladessa [460]
3 years ago
14

How many liters is 1500 ml

Mathematics
2 answers:
mrs_skeptik [129]3 years ago
7 0
1500 ml is 15 liters because 1 liter  water for example 100 ml 
Gemiola [76]3 years ago
3 0
1500 Milliliters is 1.5 liters because 1000 ml equals one liter.
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What are the points of discontinuity y=(x-5)/x^2-6x+5?
ollegr [7]
y = \frac{x - 5}{x^{2} - 6x + 5}
y = \frac{x - 5}{(x - 1)(x - 5)}
y = \frac{1}{x - 1}

x - 1 = 0
  + 1  + 1
     x = 1
3 0
2 years ago
Mary is spending money at the average rate of $5 per day. After 14 days she has $68 left. The amount left depends on the number
Radda [10]

Answer:

A. Y-68=-5(x-14)

Step-by-step explanation:

Mary is spending money at the average rate of $5 per day. After 14 days she has $68 left. The amount left depends on the number of days that have passed. write an equation for the situation

We find the equation using the point slope equation of a line. This is given as:

y - y1 = m(x-x1)

The slope intercept form will be

y = -5x + b

since the amount decreases by $5 per day...

Our slope is -5 so m=-5

We have a point (x1,y1) = (14, 68)

Hence, we have:

y-68 = -5(x-14)

Option A is correct

4 0
3 years ago
Which equation shows y=−12x+4 in standard form?
Tema [17]
The answer is the first option

6 0
2 years ago
What is 3 copies of 1/3
jarptica [38.1K]

Answer: 1

Step-by-step explanation:

3 copies of 1/3 would be 1/3+1/3+1/3= 1

6 0
3 years ago
The population of a type of local dragonfly can be found using an infinite geometric series where a1 = 65 and the common ratio i
hram777 [196]
In mathematics, number sequencing of the same pattern are called progression. There are three types of progression: arithmetic, harmonic and geometric. The pattern in arithmetic is called common difference, while the pattern in geometric is called common ratio. Harmonic progression is just the reciprocal of the arithmetic sequence.

The common ratio is denoted as r. For values of r<1, the sum of the infinite series is equal to

S∞ = A₁/(1-r), where A1 is the first term of the sequence. Substituting A₁=65 and r=1/6:

S∞ = A₁/(1-r) = 65/(1-1/6)
S∞ = 78


6 0
3 years ago
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