Question

PLEASE I NEED HELP! THANK YOU.

Answer 1

First set up a linear equation  and using the x and y values in the table see if it solves.

It doesn't solve so we know it isn't linear. ( I won't show all those steps because they aren't needed.)

Using the quadratic formula y = ax^2 +bx +c

Build a set of 3 equations from the table:

C is the Y intercept ( when X is 0), this is shown in the table as 6

Now we have y = ax^2 + bx + 6

-2.4 =4a-2b +6

1.4 = a-b +6

Rewrite the equations

a=b/2 -2.1

1.4 = b/2-2.1 +6

b = 5

a = 5/2 -2.1 = 0.4

replace the letters to get y = 0.4x^2 + 5x +6