There are three consecutive integers. The product of the first and the last is 35 more than 5 times the second number. Find thes e integers. Will give brainliest to best answer will give thanks and 5 stars rating to good answers! Please show all work (don't show 5+4 = 9 but you get the idea)
2 answers:
Answer:
8,9,10
Step-by-step explanation:
Let x-1, x and x+1 be the consecutive integers
(x-1)(x+1) = 5x + 35
x² - 1 - 5x - 35 = 0
x² - 5x - 36 = 0
x² - 9x + 4x - 36= 0
x(x - 9) + 4(x - 9) = 0
(x - 9)(x + 4) = 0
x = 9, -4
Answer:
Step-by-step explanation:
hello :
let this three consecutive integers : x , x+1 , x+2
x(x+2)=35+5(x+1)
x²+2x=35+5x+5
x²-3x-40=0
(x-8)(x+5)=0 .... x+5 ≠ 0 because : x integer
x-8=0 so : x=8
three consecutive integers are : 8 and 9 and 10
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Step-by-step explanation:
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Step-by-step explanation:
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