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2 years ago

X+5 divided by 2 equals -4. What does the x equal

Mathematics

2 answers:

asambeis [7]2 years ago

6 0

Answer:

x= -13

Step-by-step explanation:

$\frac{x+5}{2} =-4$

-4(2)=-8

-8-5=-13

x=-13

evablogger [386]2 years ago

5 0

Answer:

x=-13

Step-by-step explanation:

x+5/2=-4

we need to isolate x, so the first thing we do is get rid of the thing being divided by x, by doing the opposite: we multiply

(2) x+5/2 =-4(2)

x+5=-8

subtract 5 from both sides to isolate x

x+5-5=-8-5

x=-13

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Vsevolod [243]

Answer:

$\dfrac{-1}{6}$

Step-by-step explanation:

Given the limit of a function expressed as $\lim_{ x\to \ 0} \dfrac{sin(x)-tan(x)}{x^3}$ , to evaluate the following steps must be carried out.

Step 1: substitute x = 0 into the function

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Step 3: substitute x = 0 into the resulting function

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Step 6: Apply L'Hôpital's rule, by differentiating the numerator and denominator of the resulting function in step 4

$= \lim_{ x\to \ 0} \dfrac{\frac{d}{dx}[ -sin(x)-2sec^2(x)tan(x)]}{\frac{d}{dx} (6x)}\\= \lim_{ x\to \ 0} \dfrac{[ -cos(x)-2(sec^2(x)sec^2(x)+2sec^2(x)tan(x)tan(x)]}{6}\\\\= \lim_{ x\to \ 0} \dfrac{[ -cos(x)-2(sec^4(x)+2sec^2(x)tan^2(x)]}{6}\\$

Step 7: substitute x = 0 into the resulting function in step 6

$= \dfrac{[ -cos(0)-2(sec^4(0)+2sec^2(0)tan^2(0)]}{6}\\\\= \dfrac{-1-2(0)}{6} \\= \dfrac{-1}{6}$

Hence the limit of the function $\lim_{ x\to \ 0} \dfrac{sin(x)-tan(x)}{x^3} \ is \ \dfrac{-1}{6}$ .

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