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blondinia [14]
3 years ago
11

Rules for exponents help?

Mathematics
1 answer:
JulijaS [17]3 years ago
5 0

Your given expression has no "b", so you can rule out selections b, c, e.

The expression is not equal to 1, so you can rule out selection a.

That leaves selection d, which is the correct choice:

... d. 1/x^a

_____

The rule for exponents is that an exponent in the numerator is the same as its opposite in the denominator, and vice versa.

The exponent of <em>-a</em> in the numerator is the same as an exponent of <em>a</em> in the denominator.

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The success of an airline depends heavily on its ability to provide a pleasant customer experience. One dimension of customer se
tankabanditka [31]

Answer:

A)H0: μ1 − μ2 = 0

Ha: μ1 − μ2 ≠ 0

(b)  Means

Company A___50.6___ min.

Company B___52.75___ min.

c)The t-value is -0.30107.

The p-value is 0 .764815.

C) Do not reject H0. There is no statistical evidence that one airline does better than the other in terms of their population mean delay time.

Step-by-step explanation:

A)H0: μ1 − μ2 = 0

i.e there is no difference between the means of delayed flight for two different airlines

Ha: μ1 − μ2 ≠ 0

i.e there is a difference between the means of delayed flight for two different airlines

(b)

Company A___50.6___ min.

Company B___52.75___ min.

Mean of Company A = x`1= ∑x/n =34+ 59+ 43+ 30+ 3+ 32+ 42+ 85+ 30+ 48+ 110+ 50+ 10+ 26+ 70+ 52+ 83+ 78+ 27+ 70+ 27+ 90+ 38+ 52+ 76/25

= 1265/25= 50.6

Mean of Company B = x`2= ∑x/n =

=46+ 63+ 43+ 33+ 65+ 104+ 45+ 27+ 39+ 84+ 75+ 44+ 34+ 51+ 63+ 42+ 34+ 34+ 65+ 64/20

= 1055/20= 52.75

<u><em>Difference Scores Calculations</em></u>

Company A

Sample size for Company A= n1= 25

Degrees of freedom for company A= df1 = n1 - 1 = 25 - 1 = 24

Mean for Company A= x`1=  50.6

Total Squared Difference (x-x`1) for Company A= SS1: 16938

s21 = SS1/(n1 - 1) = 16938/(25-1) = 705.75

Company B

Sample size for Company B= n1= 20

Degrees of freedom for company B= df2 = n2 - 1 = 20 - 1 = 19

Mean for Company B= x`2=  52.75

Total Squared Difference (x-x`2) for Company B= SS2=7427.75

s22 = SS2/(n2 - 1) = 7427.75/(20-1) = 390.93

<u><em>T-value Calculation</em></u>

<u><em>Pooled Variance= Sp²</em></u>

Sp² = ((df1/(df1 + df2)) * s21) + ((df2/(df2 + df2)) * s22)

Sp²= ((24/43) * 705.75) + ((19/43) * 390.93) = 566.65

s2x`1 = s2p/n1 = 566.65/25 = 22.67

s2x`2 = s2p/n2 = 566.65/20 = 28.33

t = (x`1 - x`2)/√(s2x`1 + s2x`2) = -2.15/√51 = -0.3

The t-value is -0.30107.

The total degrees of freedom is = n1+n2- 2= 25+20-2=43

The critical region for two tailed test at significance level ∝ =0.05 is

t(0.025) (43) = t > ±2.017

Since the calculated value of t=  -0.30107.  does not fall in the critical region t > ±2.017, null hypothesis is not rejected that is there is no difference between the means of delayed flight for two different airlines.

The p-value is 0 .764815. The result is not significant at p < 0.05.

7 0
3 years ago
The black triangle was transformed to make the gray triangle. Write an
sergeinik [125]

Answer:

m<4 = 117 degrees

Step-by-step explanation:

Knowing that angle 1 is 63 degrees, we can look at the other angle on the same side of the line, angle 4.

Angles on one side of a line add to 180 degrees.

180 - 63 = 117

6 0
3 years ago
Given the statement, TSR: ABC and the diagram
coldgirl [10]
5+5 x 8 dodn yes ok ok i agree
8 0
3 years ago
The atomic weight of an unknown element,in atomic mass units (amu),is approximately 20% less than that of calcium. The atomic we
Mnenie [13.5K]
Amu of unknown element = 40 - (20% * 40)
= 40 - 8
= 38 amu

therefore, the approximate weight of the unknown element is 38 amu.

hope this helps.
4 0
3 years ago
Read 2 more answers
Evaluate the expression when a = 3 and b = 5.
dimulka [17.4K]
C would be the answer or 8
5 0
3 years ago
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