It may help to draw a picture as you start planning this problem and draw a circle, showing a circle which represents the scale needle's range of motion 360 degrees around. The needle length will then be the radius of that circle.
We know that the needle rotated 68 degrees and are trying to find the distance it traveled in cm. To find out how far the needle traveled, we need to find the arc length - in this case, the distance between the needle's starting point and where it ended up after the oranges were placed on the scale on the circle.
There is a formula you can easily use to find the arc length
arc length = 2*

*r (

)
We need to input the radius, r into this formula, as well as the central angle measure c, which in this case is 68 degrees.
2

(16) (

)
If you multiply the above formula components all together using a calculator, you will get ~18.99. (When rounded to the second decimal place.)
So, the answer is around 19 cm. (Your answer may vary depending on how your teacher usually wants you to round answers.)
Answer:
16-2n=-8+4n-12
16+8+12=4n
36/4=n
9=n
Step-by-step explanation:
Answer:
is this a question?
Step-by-step explanation:
Given:

To find:
Select the true statements from the given options about the given value.
Solution:
We have,

It can be written as

![[\because \log(ab)=\log a+\log b]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%5Clog%28ab%29%3D%5Clog%20a%2B%5Clog%20b%5D)



Clearly, the value of x lies between 4 and 5. So,
and
.
Therefore, the correct options are C and D.
Answer: It does not confirm that ΔABC∼ΔA'B'C by the AA criterion as the measure of angle B is negative which is not possible.
Step-by-step explanation:
Since we have given that
In ΔABC,
∠A = 8x - 10, ∠B = 10x - 40, and ∠C = 3x + 20
In ΔA'B'C',
∠A' = 6x + 10, ∠B' = 70 - x, and ∠C' = 10x 2
Since ΔABC gets a dilation by a scale factor of 
So, it becomes,

Now, put the value of

It does not confirm that ΔABC∼ΔA'B'C by the AA criterion as the measure of angle B is negative which is not possible.