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3 years ago

6

Use the image below to answer the following question.

1 answer:

Rainbow [258]3 years ago

3 0

Answer:9

Step-by-step explanation:pp

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Helpp please thanksss

Brilliant_brown [7]

Answer:

The function show the value of the machinery after "t" years.

So After "4" years... Input "t" as 4 to get its value

f(t) = 12,500 - 1,600(4)

=$6,100

OPTION C IS LEGIT!!!

8 0

3 years ago

Three out of every five students wore green on St. Patrick's Day. What percent of the students wore green?

aivan3 [116]

60% must be the right answer

6 0

3 years ago

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4. (10 points) From the given triangle:

katrin2010 [14]

Answer:

sinθ = y/r sinθ = $\frac{-6}{10} = \frac{-3}{5}$

cosθ = x/r cosθ = $\frac{8}{10} = \frac{4}{5}$

tanθ = y/x tanθ = $\frac{-6}{8} =\frac{-3}{4}$

cscθ = r/y cscθ = $\frac{-5}{3}$

secθ = r/x secθ = $\frac{5}{4}$

cotθ = x/y cotθ = $\frac{4}{3}$

explanation:

r = $\sqrt{(8)^{2}+(-6)^{2} }$

r = 10

x = 8

y = -6

r = $\sqrt{(4)^{2}+(3)^{2} }$

r = 5

x = 4

y = 3

7 0

3 years ago

What does 3+5x6-1=? and ill mark as brainliest

inna [77]

Answer:

32

Step-by-step explanation:

3+30-1

33-1

32

6 0

3 years ago

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Determine determine whether the following geometric series converges or diverges. if the series converges find its sum.

Lilit [14]

For starters,

$\dfrac{3^k}{4^{k+2}}=\dfrac{3^k}{4^24^k}=\dfrac1{16}\left(\dfrac34\right)^k$

Consider the $n$ th partial sum, denoted by $S_n$ :

$S_n=\dfrac1{16}\left(\dfrac34\right)+\dfrac1{16}\left(\dfrac34\right)^2+\dfrac1{16}\left(\dfrac34\right)^3+\cdots+\dfrac1{16}\left(\dfrac34\right)^n$

Multiply both sides by $\frac34$ :

$\dfrac34S_n=\dfrac1{16}\left(\dfrac34\right)^2+\dfrac1{16}\left(\dfrac34\right)^3+\dfrac1{16}\left(\dfrac34\right)^4+\cdots+\dfrac1{16}\left(\dfrac34\right)^{n+1}$

Subtract $S_n$ from this:

$\dfrac34S_n-S_n=\dfrac1{16}\left(\dfrac34\right)^{n+1}-\dfrac1{16}\left(\dfrac34\right)$

Solve for $S_n$ :

$-\dfrac14S_n=\dfrac3{64}\left(\left(\dfrac34\right)^n-1\right)$

$S_n=\dfrac3{16}\left(1-\left(\dfrac34\right)^n\right)$

Now as $n\to\infty$ , the exponential term will converge to 0, since $r^n\to0$ if $0$ . This leaves us with

$\displaystyle\lim_{n\to\infty}S_n=\lim_{n\to\infty}\sum_{k=1}^n\frac{3^k}{4^{k+2}}=\sum_{k=1}^\infty\frac{3^k}{4^{k+2}}=\frac3{16}$

8 0

3 years ago

Read 2 more answers