Answer:
7w+11
Step-by-step explanation:
GEMDAS
Ok, here we go. Pay attention. The formula for the arc length is

. That means that to use that formula we have to find the derivative of the function and square it. Our function is y = 4x-5, so y'=4. Our formula now, filled in accordingly, is

(that 1 is supposed to be negative; not sure if it is til I post the final answer). After the simplification we have the integral from -1 to 2 of

. Integrating that we have

from -1 to 2.

gives us

. Now we need to do the distance formula with this. But we need 2 coordinates for that. Our bounds are x=-1 and x=2. We will fill those x values in to the function and solve for y. When x = -1, y=4(-1)-5 and y = -9. So the point is (-1, -9). Doing the same with x = 2, y=4(2)-5 and y = 3. So the point is (2, 3). Use those in the distance formula accordingly:

which simplifies to

. The square root of 153 can be simplified into the square root of 9*17. Pulling out the perfect square of 9 as a 3 leaves us with

. And there you go!
Answer: 2 quarters = 50 cents, 3 dimes = 30 cents, 4 nickels =20 cents. 50+30+20=100 cents.
Step-by-step explanation:
Answer:
We conclude that at x = 0 and x = -1, the value of f(x) = 2ˣ - 1 and g(x) = 1/2x is the same.
Therefore, the solution to f(x) = g(x) is:
Step-by-step explanation:
Given the table
x f(x) = 2ˣ - 1 g(x) = 1/2x
-2 -3/4 -1
-1 -1/2 -1/2
0 0 0
1 1 1/2
2 3 1
If we carefully observe, we can determine that
at x = 0, the value of f(x) = 2ˣ - 1 and g(x) = 1/2x is the same.
In other words,
at x = 0
Thus,
at x = 0
f(x) = g(x)
Also at x = -1, the value of f(x) = 2ˣ - 1 and g(x) = 1/2x is the same.
In other words,
at x = -1
Thus,
at x = -1
f(x) = g(x)
Summary:
Thus, we conclude that at x = 0 and x = -1, the value of f(x) = 2ˣ - 1 and g(x) = 1/2x is the same.
Therefore, the solution to f(x) = g(x) is: