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V125BC [204]
3 years ago
11

Suppose you can replace one number cube with a nonstandard number cube, where any of the numbers 1 through 6 can appear on multi

ple faces. How can you arrange the numbers on the nonstandard cube so that the mean of the rolls is the same as that of two standard number cubes, but the standard deviation is as large as possible? What is this value? Explain your thinking
Mathematics
1 answer:
vagabundo [1.1K]3 years ago
8 0

Answer:

Replace 5 and 4 with 6s. Replace 2 and 3 with 1s. Then there will be 3 faces with 6 and 3 faces with 1.

Step-by-step explanation:

In order for the mean to remain unchanged, the sum of opposite faces must remain the same: 7. In order to have the standard deviation as large as possible, the largest and smallest possible numbers need to be used: 6 and 1.

Replacing 4 and 5 with 6s, and replacing 2 and 3 with 1s will accomplish your goal.

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3 years ago
Simplify -3p 3 + 5p + (-2p 2) + (-4) - 12p + 5 - (-8p 3).
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open brackets

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