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V125BC [204]
3 years ago
11

Suppose you can replace one number cube with a nonstandard number cube, where any of the numbers 1 through 6 can appear on multi

ple faces. How can you arrange the numbers on the nonstandard cube so that the mean of the rolls is the same as that of two standard number cubes, but the standard deviation is as large as possible? What is this value? Explain your thinking
Mathematics
1 answer:
vagabundo [1.1K]3 years ago
8 0

Answer:

Replace 5 and 4 with 6s. Replace 2 and 3 with 1s. Then there will be 3 faces with 6 and 3 faces with 1.

Step-by-step explanation:

In order for the mean to remain unchanged, the sum of opposite faces must remain the same: 7. In order to have the standard deviation as large as possible, the largest and smallest possible numbers need to be used: 6 and 1.

Replacing 4 and 5 with 6s, and replacing 2 and 3 with 1s will accomplish your goal.

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Answer:

60

Step-by-step explanation:

25÷5=5

5×12=60

have a great day! :)

4 0
3 years ago
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How many things can happen if you spin the spinner three times and flip the coin three times?
vladimir2022 [97]

Answer:

8

Step-by-step explanation:

8 possible outcomes

We can now extend this thinking. If we toss three coins, we have a total of 2 × 2 × 2 = 8 possible outcomes: HHH, HHT, HTH, HTT, THH, THT, TTH, and TTT.

7 0
3 years ago
In the diagram of O, m∠JOK = 60° and OJ = 6 in. What is the exact area of the shaded region?
Sophie [7]

Answer:   6π

<u>Step-by-step explanation:</u>

Area of a circle is π r².

Area of a section of a circle is π r² × the section of the circle.

A=\pi r^2\bigg(\dfrac{\theta}{360^o}\bigg)

Given: r = 6, Ф = 60°

A=\pi (6)^2\bigg(\dfrac{60^o}{360^o}\bigg)\\\\\\.\quad =\pi (6)^2\bigg(\dfrac{1}{6}\bigg)\\\\\\.\quad =6\pi

3 0
3 years ago
The mayor of a town believes that over 47G% of the residents favor construction of an adjoining community. Is there sufficient e
photoshop1234 [79]

Answer:

There is sufficient evidence at the 0.05 level

Null hypothesis ; H0 : p = 0.47

Alternative hypothesis : H1 : p ≠ 0.47

Step-by-step explanation:

percentage favoring construction of adjoining community = 47%

level = 0.05

To determine if the 0.05 confidence level is enough to support the major's claim we have to state the Null and alternative hypothesis

Null hypothesis ; H0 : p = 0.47

Alternative hypothesis : H1 : p ≠ 0.47

5 0
3 years ago
Each month the fire department host a pancake feed. This month 75 people attended the pancake feed. This is 13 less than twice a
Kazeer [188]
75=2x-13
75+13=2x-13+13
88=2x
88÷2=2x÷2
44=x
7 0
3 years ago
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