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erma4kov [3.2K]
3 years ago
7

A construction crew will build a new railroad track which passes through the point​ (8,5) and is parallel to the one modeled by

the line. What equation models the path of the new​ track
Mathematics
1 answer:
Mrac [35]3 years ago
7 0

Answer:

Lines a and c have the same slope, so they are parallel. Write an equation of the line that passes through (5, −4) and is parallel to the line y = 2x + 3. Step 1 Find the slope of the parallel line. The graph of the given equation has a slope of 2.

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In the game of​ roulette, a player can place a ​$4 bet on the number 29 and have a 1/38 probability of winning. If the metal bal
creativ13 [48]

Answer:

The expected value of the game to the player is -$0.2105 and the expected loss if played the game 1000 times is -$210.5.

Step-by-step explanation:

Consider the provided information.

It is given that if ball lands on 29 players will get $140 otherwise casino will takes $4.

The probability of winning is 1/38. So, the probability of loss is 37/38.

Now, find the expected value of the game to the player as shown:

E(x)=(140)\times \frac{1}{38}+(-4)\times \frac{37}{38}

E(x)=\frac{140-148}{38}

E(x)=\frac{-8}{38}=-$0.2105

Hence, the expected value of the game to the player is -$0.2105.

Now find the expect to loss if played the game 1000 times.

1000×(-$0.2105)=-$210.5

Therefore, the expected loss if played the game 1000 times is -$210.5.

5 0
3 years ago
Help please ! I’m stuck
Troyanec [42]
Y=1x-10 (sorry I could be wrong)
4 0
3 years ago
A company's board of directors wants to form a committee of
NeTakaya

1∪ 2/3.....................

8 0
3 years ago
Help me please i really need this im failing pls try to understand and help me
hammer [34]
It’s option B. Because that’s the try statement.
8 0
3 years ago
Read 2 more answers
A 3.00-g copper penny at 25.0°C drops from a height of50.0 m to the ground. (
Gnoma [55]
The potential energy, E, of the penny is given by E=mgh.  The energy, Q, required to raise the temperature of an object by an amount ΔT is given by Q=mcΔT.  We can equate these two to get the result but we must use proper units and include the 60%:
(0.6)mgh=mcΔT
We see we can divide out the mass from each side
0.6gh=cΔT,   then 0.6gh/c=ΔT
(0.6)9.81(m/s²)50m/385(J/kg°C) = 0.7644°C
since this is the change in temperature and it started at 25°C we get
T=25.7644°C
As you can see the result does not depend on mass.  The more massive the copper object the more potential energy it will have to contribute to the heat energy, but the more stuff there will be to heat up, and the effect is that the mass cancels.
6 0
3 years ago
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