Question

NEED HELP PLEASE WILL GIVE BRANLIEST !!!!!!!!!!!!!

Answer 1

Look at the picture.

Angles KJL and SRT are Corresponding angles. JK is parallel to RS. Therefore

m∠KJL = m∠SRT

A. The slope of JL is equal to the slope of RT.

Other method.

Calculate the slope.

The formula of a slope:

$m=\dfrac{y_2-y_1}{x_2-x_1}$

We have the points J(-6, -6) and L(2, -2). Substitute:

$m=\dfrac{-2-(-6)}{2-(-6)}=\dfrac{-2+6}{2+6}=\dfrac{4}{8}=\dfrac{1}{2}$

The slope of JL is 1/2.

We have the points R(4, -1) and T(8, 1). Substitute:

$m=\dfrac{1-(-1)}{8-4}=\dfrac{1+1}{4}=\dfrac{2}{4}=\dfrac{1}{2}$

The slope of RT is 1/2.