Question

Plz plz plz help me....

Answer 1

Answer:

Let the tens digit of the required number be x and the units digit be y. Then,

x+y=12 .........(1)

Required Number = (10x+y).

Number obtained on reversing the digits = (10y+x).

Therefore,

(10y+x)−(10x+y)=18

9y−9x=18

y−x=2 ..........(2)

On adding (1) and (2), we get,

2y=14⟹y=7

Therefore,

x=5

Hence, the required number is 57.

Step-by-step explanation:

Hope it is helpful...

Answer 2

Step-by-step explanation:

Let X be the 1st digit and Y be the 2nd digit of the two digit number.

We have X * Y = 12 and (10X + Y) = (10Y + X) + 9.

=> XY = 12 and 9X = 9Y + 9

=> XY = 12 and X = Y + 1

Therefore X = 4 and Y = 3. => Number is 43.