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3 years ago

Solve for x. A. 6 B. 8 C. 12 D. 18

Mathematics

2 answers:

marysya [2.9K]3 years ago

8 0

$we \: get \\ \frac{24}{x} = \frac{36}{12} \\ \implies x \: = \frac{12 \times 24}{36} \\ \implies x = \frac{288}{36} \\ \implies \: x = 8 \\ hence \: x = 8$

uranmaximum [27]3 years ago

4 0

36/12 = 24/x
432/24x
X=18

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Please help me! A soup can, shaped like a cylinder, has a diameter of 3.5 inches and a height of 5 inches. Each serving of soup

SpyIntel [72]

The cost for each serving of soup is $0.62

Step-by-step explanation:

Diameter =3.5 inches

Radius = 1.75 inches

Height = 5 inches

Each serving of soup = 15 cubic inches

Cost of the can = $1.99

Volume of the can = π(1.75 x 1.75) 5

= (3.14) (3.0625) 5

= 48.08 cubic inches

For 48 cubic inches of soup the cost is $1.99

For 15 cubic inches of soup the coat will be,

Cost = (15x1.99) /48

= $0.62

The cost for each serving of soup is $0.62

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3 years ago

Dan scored 87 on his math test. The

Dmitry_Shevchenko [17]

Answer:69.15

Step-by-step explanation: the deviation is 6 which and 1/6 of people got the same grade as him - 100 = 69.15

5 0

3 years ago

2(3 – 4a) + 5(a – 7)

PilotLPTM [1.2K]

Answer:

The answer is -(29+3a).

Step-by-step explanation:

=2(3-4a)+5(a-7)

= 6- 8a +5a -35

= 6-35-8a+5a

= -29-3a

= -(29+3a)

Hope it helps..

6 0

3 years ago

Read 2 more answers

Amy is pulling a wagon with a force of 30 pounds up a hill at an angle of 25°. Give the force exerted on the wagon as a vector a

Fofino [41]

Answer:

Vector (ordered pair - rectangular form)

$\vec F = (27.189,12.679)\,[lbf]$

Vector (ordered pair - polar form)

$\vec F = (30\,lbf, 25^{\circ})$

Sum of vectorial components (linear combination)

$\vec F = 27.189\cdot \hat{i} + 12.679\cdot \hat{j}\,[N]$

Step-by-step explanation:

From statement we know that force exerted on the wagon has a magnitude of 30 pounds-force and an angle of 25° above the horizontal, which corresponds to the +x semiaxis, whereas the vertical is represented by the +y semiaxis.

The force ( $\vec F$ ), in pounds-force, can be modelled in two forms:

Vector (ordered pair - rectangular form)

$\vec F = \left(\|\vec F\|\cdot \cos \theta, \|\vec F\|\cdot \sin \theta\right)$ (1)

Vector (ordered pair - polar form)

$\vec F = \left(\|\vec F\|, \theta\right)$

Sum of vectorial components (linear combination)

$\vec {F} = \left(\|\vec F\|\cdot \cos \theta\right)\cdot \hat{i} + \left(\|\vec F\|\cdot \sin \theta \right)\cdot \hat{j}$ (2)

Where:

$\|\vec F\|$ - Norm of the vector force, in newtons.

$\theta$ - Direction of the vector force with regard to the horizontal, in sexagesimal degrees.

$\hat{i}$ , $\hat{j}$ - Orthogonal axes, no unit.

If we know that $\|\vec F\| = 30\,lbf$ and $\theta = 25^{\circ}$ , then the force exerted on the wagon is:

Vector (ordered pair - rectangular form)

$\vec F= \left(30\cdot \cos 25^{\circ}, 30\cdot \sin 25^{\circ}\right)\,[lbf]$

$\vec F = (27.189,12.679)\,[lbf]$

Vector (ordered pair - polar form)

$\vec F = (30\,lbf, 25^{\circ})$

Sum of vectorial components (linear combination)

$\vec F = (30\cdot \cos 25^{\circ})\cdot \hat{i} + (30\cdot \sin 25^{\circ})\cdot \hat{j}\,[N]$

$\vec F = 27.189\cdot \hat{i} + 12.679\cdot \hat{j}\,[N]$

8 0

2 years ago

How do you use compatible numbers to estimate the quotient $595 divided by 25

storchak [24]

Well, 25 certainly doesn't divide evenly into 595, but it does divide into 600, which is very close to 595. So if we divide 600 by 25, we can get a rough estimate of what 595 divided by 25 is.
$\frac{600}{25} = 6* \frac{100}{25} = 6* 4=24$

4 0

3 years ago