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Sever21 [200]
3 years ago
13

Solve for x. A. 6 B. 8 C. 12 D. 18

Mathematics
2 answers:
marysya [2.9K]3 years ago
8 0

we \: get \\  \frac{24}{x}  =  \frac{36}{12} \\  \implies x \:  =  \frac{12 \times 24}{36}  \\  \implies x =  \frac{288}{36}  \\ \implies \: x = 8 \\ hence \: x = 8
uranmaximum [27]3 years ago
4 0
36/12 = 24/x
432/24x
X=18
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Please help me! A soup can, shaped like a cylinder, has a diameter of 3.5 inches and a height of 5 inches. Each serving of soup
SpyIntel [72]

The cost for each serving of soup is $0.62

<u>Step-by-step explanation:</u>

Diameter =3.5 inches

Radius = 1.75 inches

Height = 5 inches

Each serving of soup = 15 cubic inches

Cost of the can = $1.99

Volume of the can = π(1.75 x 1.75) 5

= (3.14) (3.0625) 5

= 48.08 cubic inches

For 48 cubic inches of soup the cost is $1.99

For 15 cubic inches of soup the coat will be,

Cost = (15x1.99) /48

= $0.62

The cost for each serving of soup is $0.62

6 0
3 years ago
Dan scored 87 on his math test. The
Dmitry_Shevchenko [17]

Answer:69.15

Step-by-step explanation: the deviation is 6 which and 1/6 of people got the same grade as him - 100 = 69.15

5 0
3 years ago
2(3 – 4a) + 5(a – 7)
PilotLPTM [1.2K]

Answer:

The answer is -(29+3a).

Step-by-step explanation:

=2(3-4a)+5(a-7)

= 6- 8a +5a -35

= 6-35-8a+5a

= -29-3a

= -(29+3a)

<em>Hope</em><em> </em><em>it helps</em><em>.</em><em>.</em>

6 0
3 years ago
Read 2 more answers
Amy is pulling a wagon with a force of 30 pounds up a hill at an angle of 25°. Give the force exerted on the wagon as a vector a
Fofino [41]

Answer:

Vector (ordered pair - rectangular form)

\vec F = (27.189,12.679)\,[lbf]

Vector (ordered pair - polar form)

\vec F = (30\,lbf, 25^{\circ})

Sum of vectorial components (linear combination)

\vec F = 27.189\cdot \hat{i} + 12.679\cdot \hat{j}\,[N]

Step-by-step explanation:

From statement we know that force exerted on the wagon has a magnitude of 30 pounds-force and an angle of 25° above the horizontal, which corresponds to the +x semiaxis, whereas the vertical is represented by the +y semiaxis.

The force (\vec F), in pounds-force, can be modelled in two forms:

Vector (ordered pair - rectangular form)

\vec F =  \left(\|\vec F\|\cdot \cos \theta, \|\vec F\|\cdot \sin \theta\right) (1)

Vector (ordered pair - polar form)

\vec F = \left(\|\vec F\|, \theta\right)

Sum of vectorial components (linear combination)

\vec {F} = \left(\|\vec F\|\cdot \cos \theta\right)\cdot \hat{i} + \left(\|\vec F\|\cdot \sin \theta \right)\cdot \hat{j} (2)

Where:

\|\vec F\| - Norm of the vector force, in newtons.

\theta - Direction of the vector force with regard to the horizontal, in sexagesimal degrees.

\hat{i}, \hat{j} - Orthogonal axes, no unit.

If we know that \|\vec F\| = 30\,lbf and \theta = 25^{\circ}, then the force exerted on the wagon is:

Vector (ordered pair - rectangular form)

\vec F= \left(30\cdot \cos 25^{\circ}, 30\cdot \sin 25^{\circ}\right)\,[lbf]

\vec F = (27.189,12.679)\,[lbf]

Vector (ordered pair - polar form)

\vec F = (30\,lbf, 25^{\circ})

Sum of vectorial components (linear combination)

\vec F = (30\cdot \cos 25^{\circ})\cdot \hat{i} + (30\cdot \sin 25^{\circ})\cdot \hat{j}\,[N]

\vec F = 27.189\cdot \hat{i} + 12.679\cdot \hat{j}\,[N]

8 0
2 years ago
How do you use compatible numbers to estimate the quotient $595 divided by 25
storchak [24]
Well, 25 certainly doesn't divide evenly into 595, but it does divide into 600, which is <em>very</em> close to 595. So if we divide 600 by 25, we can get a rough estimate of what 595 divided by 25 is.
\frac{600}{25} = 6* \frac{100}{25} = 6* 4=24
4 0
3 years ago
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