Which of the following best describes cost-benefit analysis?

What does considering scale mean in science?

Annette [7]

Answer: scale (chemistry), the range of mass or volume of a chemical reaction or process.

Explanation:

:D h

5 0

3 years ago

Using powerpoint 2016, ethan develops a short five-slide presentation for his marketing project. â â powerpoint files consist of

Lady bird [3.3K]

b. Ribbons - Powerpoint 2016 has a tabbed ribbon system that groups relevant menus together according to category. The ribbon contains a number of tabs, each having a separate group of commands. The tabs can be used to do most of the common tasks in Powerpoint.

8 0

3 years ago

A datagram network allows routers to drop packets whenever they need to. The probability of a router discarding a packetis p. Co

tresset_1 [31]

Answer:

a.) k² - 3k + 3

b.) 1/(1 - k)²

c.) $k^{2} - 3k + 3 * \frac{1}{(1 - k)^{2} }\\\\= \frac{k^{2} - 3k + 3 }{(1-k)^{2} }$

Explanation:

a.) A packet can make 1,2 or 3 hops

probability of 1 hop = k ...(1)

probability of 2 hops = k(1-k) ...(2)

probability of 3 hops = (1-k)²...(3)

Average number of probabilities = (1 x prob. of 1 hop) + (2 x prob. of 2 hops) + (3 x prob. of 3 hops)

= (1 × k) + (2 × k × (1 - k)) + (3 × (1-k)²)

= k + 2k - 2k² + 3(1 + k² - 2k)

∴mean number of hops = k² - 3k + 3

b.) from (a) above, the mean number of hops when transmitting a packet is k² - 3k + 3

if k = 0 then number of hops is 3

if k = 1 then number of hops is (1 - 3 + 3) = 1

multiple transmissions can be needed if K is between 0 and 1

The probability of successful transmissions through the entire path is (1 - k)²

for one transmission, the probility of success is (1 - k)²

for two transmissions, the probility of success is 2(1 - k)²(1 - (1-k)²)

for three transmissions, the probility of success is 3(1 - k)²(1 - (1-k)²)² and so on

∴ for transmitting a single packet, it makes:

∞ n-1

T = ∑ n(1 - k)²(1 - (1 - k)²)

n-1

= 1/(1 - k)²

c.) Mean number of required packet = ( mean number of hops when transmitting a packet × mean number of transmissions by a packet)

from (a) above, mean number of hops when transmitting a packet = k² - 3k + 3

from (b) above, mean number of transmissions by a packet = 1/(1 - k)²

substituting: mean number of required packet = $k^{2} - 3k + 3 * \frac{1}{(1 - k)^{2} }\\\\= \frac{k^{2} - 3k + 3 }{(1-k)^{2} }$

6 0

3 years ago

Write a program with class name Digits that prompts the user to input a positive integer and then outputs the number reversed an

mr Goodwill [35]

Answer:

Written in Python:

inputnum = int(input("User Input: "))

outputnum = 0

total = 0

while(inputnum>0):

remainder = inputnum % 10

outputnum = (outputnum * 10) + remainder

inputnum = inputnum//10

total = total + remainder

print("Reverse: "+str(outputnum))

print("Total: "+str(total))

Explanation:

This prompts user for input

inputnum = int(input("User Input: "))

This initializes the reverse number to 0

outputnum = 0

This initializes total to 0; i.e. sum of each digit

total = 0

The following iteration gets the reverse of user input

while(inputnum>0):

remainder = inputnum % 10

outputnum = (outputnum * 10) + remainder

inputnum = inputnum//10

 This adds each digit of user input

total = total + remainder

This prints the reversed number

print("Reverse: "+str(outputnum))

This prints the sum of each digit

print("Total: "+str(total))

7 0

3 years ago

The text discusses three approaches to combining overall cost leadership and differentiation competitive advantages. Which of th

dedylja [7]

Answer:

C. deriving benefits from highly focused and high technology markets

Explanation:

Firms that engage in cost-leadership approach seek to combine a low per-unit income with large sales for profit making purposes. Typically, but not always, they are more inclined to market their products and services to a large population base or a niche with a high demand volume. While differentiation enables a company to accomplish a competitive advantage. A Competitive advantage enables a company to achieve more strides over other companies offering related product substitutes. It is an important marketing process that is of critical economic importance to a business.

It should be noted that deriving benefits from highly focused and high technology markets is not part of the approaches to combining overall cost leadership and differentiation competitive advantages.

3 0

3 years ago