Solution: We are given:
Using the empirical rule, we have:
covers 68% of data.
Also the percentage of values below mean = Percentage of values above mean = 50%
Now, let's find the z score for x=20
Therefore, the percentage of values greater than 1 standard deviation above mean 
Expected number of students = 16% of 100 = 16
A.) For the Junior Varsity Team, mean would be the appropriate measure of center since the data is <span>symmetric or well-proportioned while we should use standard deviation for getting the measure of spread since it also measures the center and how far the values are from the mean.
b.) For the Varsity Team, the median would be the appropriate measure of the center since the data is skewed left and not evenly distributed so median could be used since it does not account for outliers while we use IQR or interquartile range in measuring the spread of data since IQR does not account for the data that is skewed. </span>
5x - 15 = 2x - 6
3x = 9
x = 3
Y = 5(3) - 15
Y = 0
(3,0)
12(months) x 20 (years) = 240
10.98 x 240 = 2635.20
So Arthur will pay $2635.20 over 20 years for premium.
I hope this helps :)
Answer:
The answer is 6-3 i
Step-by-step explanation:
