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Darya [45]
3 years ago
12

A submarine descended 3/5 of a kilometer in 1/5 of an hour. What was the submarine’s rate of descent in kilometers per hour?

Mathematics
2 answers:
grandymaker [24]3 years ago
3 0

Answer:

3 km per hour

Step-by-step explanation:

You can deduct the answer instinctively since both the distance and the time of the descent are expressed in /5... so you can just get rid of the '/5' in both instances to get the result: 3 kilometers in 1 hour.

But you can also find it easily using the cross-multiplication system:

\frac{3}{5} km  =  \frac{1}{5}  hour

Then you multiply each side by 5 to get

3 km = 1 hour

Thus the rate of descent is of 3 km per hour.

blagie [28]3 years ago
3 0

<u>Answer:</u>

3 kilometer per hour

<u>Step-by-step explanation:</u>

We are given that a submarine descended 3/5 of a kilometer in 1/5 of an hour and we are to find the submarine's rate of descent in kilometers per hour.

\frac{3}{5} kilometer = 0.6 kilometer

\frac{1}{5} hour = 0.2 hour

Using the ratio method to find the rate of descent:

\frac{0.6km}{x} =\frac{0.2hour}{1 hour}

x = \frac{0.6}{0.2}

x=3

Therefore, the rate of descent of submarine is 3 kilometer per hour.

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Answer:

Test statistic Z= 0.13008 < 1.96 at 0.10 level of significance

null hypothesis is accepted

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Step-by-step explanation:

<em>Step(I)</em>:-

Given surveyed two random samples of 390 men and 360 women who were tested

first sample proportion

                    p_{1} = \frac{360}{390} = 0.9230

second sample proportion

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Step(ii):-

Null hypothesis : H₀ : There is no difference  proportion of positive tests among men is different from the proportion of positive tests among women

Alternative Hypothesis:-

There is difference between proportion of positive tests among men is different from the proportion of positive tests among women

 

Z = \frac{p_{1}- p_{2} }{\sqrt{PQ(\frac{1}{n_{1} }+\frac{1}{n_{2} }  } }

where

          P = \frac{n_{1}p_{1} +n_{2}  p_{2} }{n_{1}+n_{2}  }

         P =  0.920

Z= \frac{0.9230-0.9038}{\sqrt{0.920 X0.08(\frac{1}{390}+\frac{1}{52}  } )}

Test statistic Z =  0.13008

Level of significance = 0.10

The critical value Z₀.₁₀ = 1.645

Test statistic Z=0.13008 < 1.645 at 0.1 level of significance

Null hypothesis is accepted

There is no difference proportion of positive tests among men is different from the proportion of positive tests among women







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