Since the given trinomials are with degree 2, thus, if they are perfect square, the binomial which was used to make them must be linear.

Let the binomial term was ax + b(a linear expression is always writable in this form where a and b are constants and m is a variable), then we will obtain:

$(ax + b)^2 = a^2x^2 + b^2 + 2abx$

Comparing this expression with the expression we're provided with:

$x^2 + 10x + c$

we see that:

$a^2 = 1 \implies a = \pm 1\\b^2 = 10\\b = \pm 10\\2ab = c\\\pm2(10)1 = c\\c = \pm 20\\$

Thus, the value of c for which the considered trinomial becomes perfect square trinomial is: 20 or -20

Learn more about perfect square trinomials here:

brainly.com/question/88561

6 0

2 years ago

ILL put you as brainliest

ICE Princess25 [194]

Just replace x with whatever , and see if it works. If it works then it is a solution; otherwise it's not.

1^2 is not 2
(1/2)^2 isn't 2 either...
and so on

3 0

3 years ago

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