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Sidana [21]
3 years ago
14

Matilda has 16 3/4 hours to finish 3 consulting projects. How much time may she spend on each project, if she plans to spend the

same amount of time each?
A. 5 6/7

B. 5 3/7

C. 5 9/11

D. 5 7/12

Mathematics
1 answer:
Mrac [35]3 years ago
3 0

Answer:  D

Step-by-step explanation:

To find how much time she need on each project divide the time by 3 because there are 3 projects and to get to 1 project you will need to divide by 3.

16 3/4 =  67/4

\frac{67}{4} ÷ \frac{3}{1}  = \frac{67}{12}   = 5 7/12

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Nee de idnfisneudnwshosbdiebdkdne
kirill115 [55]

Answer:

x = 20

Step-by-step explanation:

The scale factor is 2.5. The arrow on the right is 2.5 times bigger than the arrow on the left. So, you would multiply 8 by 2.5 to find x.

8 x 2.5 = 20

Please mark Brainliest :)

7 0
3 years ago
The value of a professional basketball player's autograph rose 20% in the last year. It is now worth $336.00. What was it worth
sesenic [268]

Answer:

The value of basketball player's autograph a year ago is $280

Step-by-step explanation:

Given as :

The present value of autograph = $ 336.00

The rate of increase of autograph = 20%

The time period = 1 year

Let The value one year ago = $ x

So ,

The value of autograph after n year = The present value × (1+\frac{Rate}{100})^{n}

Or, $ 336.00 = $ x × (1+\frac{20}{100})^{1}

Or, $ 336.00 = $x × 1.2

∴ x = \frac{336.00}{1.2} = $280

Hence The value of basketball player's autograph a year ago is $280 Answer

6 0
3 years ago
17
Sauron [17]

let's firstly find the equation of the parabola, bearing in mind that x-intercepts or solutions/zeros/roots means y = 0.

\bf ~~~~~~\textit{vertical parabola vertex form} \\\\ y=a(x- h)^2+ k\qquad \begin{cases} \stackrel{vertex}{(h,k)} \end{cases} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \begin{cases} h=1\\ k=-9 \end{cases}\implies y=a(x-1)^2-9 \\\\\\ \textit{we also know that } \begin{cases} x=0\\ y=-6 \end{cases}\implies -6=a(0-1)^2-9\implies 3=a(-1)^2

\bf 3=a\qquad \qquad \textit{therefore}\qquad \qquad \boxed{y=3(x-1)^2-9} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{y}{0}=3(x-1)^2-9\implies 9=3(x-1)^2\implies \cfrac{9}{3}=(x-1)^2\implies 3=(x-1)^2 \\\\\\ \pm\sqrt{3}=x-1\implies \pm\sqrt{3}+1=x\implies x= \begin{cases} \sqrt{3}+1\\ -\sqrt{3}+1 \end{cases}\implies x\approx \begin{cases} 2.73\\ -0.73 \end{cases}

8 0
3 years ago
Read 2 more answers
I need some assistance on finding the arc measure
Kitty [74]
D to B =180
B to D=180
D to C =19
7 0
4 years ago
What should Jayce conclude is the distance around the largest circle on the radar screen? Use pi = 3.14.
anastassius [24]

Answer:

it would end up right in the dot hope this helped :)

Step-by-step explanation:

5 0
3 years ago
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