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nasty-shy [4]
3 years ago
12

Given f(x) = –5x + 1, what is f(–2)?

Mathematics
1 answer:
DiKsa [7]3 years ago
3 0
F(x) = -5x + 1

f(-2) = -5(-2) + 1
f(-2) = 10 + 1
f(-2) = 11

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Answer: f(-2) = 11 (Answer C)
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PreCalc work, Need help with writing piece wise functions with graphs level 2. Giving branliest.
Natalija [7]

The piece-wise linear functions can be written as follows:

  • f(x) = -0.5x + 3, x < 5.
  • f(x) = -5, x = 5
  • f(x) = -x  + 9, x > 5.

<h3>What is a linear function?</h3>

A linear function is modeled by:

y = mx + b

In which:

  • m is the slope, which is the rate of change, that is, by how much y changes when x changes by 1.
  • b is the y-intercept, which is the value of y when x = 0, and can also be interpreted as the initial value of the function.

For x less than 5, the y-intercept is of b = 3 and the function also gos through (2,2), hence the slope is:

m = (2 - 3)/(2 - 0) = -0.5.

Hence the rule is:

f(x) = -0.5x + 3, x < 5.

When x = 5, the function is constant at -5, hence:

f(x) = -5, x = 5

For x less than 5, the function goes through points (6,3) and (7,2), hence the slope is:

m = (2 - 3)/(7 - 6) = -1.

Then:

y = -x + b

When x = 6, y = 3, hence the y-intercept is given as follows:

3 = -6 + b

b = 9.

Hence the rule is:

f(x) = -x  + 9, x > 5.

More can be learned about linear functions at brainly.com/question/25537936

#SPJ1

3 0
2 years ago
What is sin θ when sec θ = square root of 5? Rationalize the denominator if necessary.
alexandr1967 [171]

\bf sec(\theta )=\sqrt{5}\implies \cfrac{1}{cos(\theta )}=\sqrt{5}\implies \cfrac{\stackrel{adjacent}{1}}{\stackrel{hypotenuse}{\sqrt{5}}}=cos(\theta )~\hfill \leftarrow \stackrel{\textit{let's find the}}{\textit{opposite side}} \\\\\\ \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies \pm\sqrt{c^2-a^2}=b \qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ \end{cases}

\bf \pm\sqrt{(\sqrt{5})^2-1^2}=b\implies \pm\sqrt{5-1}=b\implies \pm\sqrt{4}=b\implies \pm 2=b \\\\[-0.35em] ~\dotfill\\\\ sin(\theta )=\pm\cfrac{\stackrel{opposite}{2}}{\stackrel{hypotenuse}{\sqrt{5}}}\implies \stackrel{\textit{rationalizing the denominator}}{\pm\cfrac{2}{\sqrt{5}}\cdot \cfrac{\sqrt{5}}{\sqrt{5}}\implies \pm\cfrac{2\sqrt{5}}{(\sqrt{5})^2}\implies \pm\cfrac{2\sqrt{5}}{5}}

7 0
3 years ago
Read 2 more answers
5x (x+8)= - 7 quadratic or not? explain, ​
mote1985 [20]

Answer:

Step-by-step explanation:

Yes it is a quadratic equation

5x^2 + 40x = -7

5x^2 + 40x + 7 = 0

a = 5

b = 40

c = 7

-40/10 <u>+</u> (sqrt(1600 - 4(5)(7)))/10

-4 <u>+</u> (sqrt(1600-160))/10

-4 <u>+</u> (sqrt(1440))/10

-4 <u>+</u> 12(sqrt(10))/10

-4 <u>+</u> 6/5(sqrt(10))

6 0
4 years ago
The pythagorean theorem i need help!!
netineya [11]

Using the Pythagorean theorem:

X = sqrt(26^2 - 10^2)

X = sqrt(676-100)

X = sqrt(576)

X = 24

Answer: 24

4 0
3 years ago
13. Diberi v = u + at, cari nilai t apabila v = v = 42 u=-8 dana - 5. <br>A.10<br>B.8<br>C.6<br>D.4​
LiRa [457]

Answer:

Lol mcm soalan kamu salah. Pilih A je

Step-by-step explanation:

  • v = 42
  • u = -8
  • a = -5

<u>Masukkan </u><u>nilai </u><u>ters</u><u>e</u><u>b</u><u>ut </u><u>dalam</u><u> </u><u>persamaan</u><u> </u><u>v</u><u> </u><u>=</u><u> </u><u>u </u><u>+</u><u> </u><u>at,</u>

42 = -8 + (-5)t

50 = -5t

t = -10

3 0
3 years ago
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