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podryga [215]
3 years ago
5

if it is p miles from home to school how many round trips can be made if your car gets q miles per gallon of gasoline and there

are 5 gallons of gas in its tank
Mathematics
1 answer:
Bumek [7]3 years ago
3 0
5 is less than or equal to (2q)/p
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(a) Predict the median income of a region in which 30% of adults 25 years and older have at least a bachelor's degree.
Step2247 [10]

Answer:

(a). $35746. (b). Higher.

Step-by-step explanation:

(a). Given that the least-squares regression equation is y = 7163x + 14242. Also, in the question above we are given that y is the median income and x is the percentage of 25 years and older with at least a bachelor's degree in the region, that is to say that the value of x = 30.

Therefore, y = 7163x + 14242.

y = (7163 × 30) + 14242.

y = $35746.

(b). The condition for our x is; 28.7 percent of adults 25 years and older have at least a bachelor's degree.

Then, y = (7163 × 28.7) + 14242.

y = $34814.

Hence, we have the median income in this region = $38,163 HIGHER than $34814.

4 0
3 years ago
Sienna is solving the quadratic equation by completing the square.
pantera1 [17]

Answer:

See below

Step-by-step explanation:

3 (x^2 + 3x) = 4

3 ( x + 3/2)^2   = 4 + 27/4  

4 0
2 years ago
5
labwork [276]
This is called the Pythagorean theorem : a ² + b ² = c ². You can substitute any of the variable with any of the known numbers and then you all you have to do is isolate the variable. I hope that helps!!
4 0
3 years ago
A set of sweater prices are normally distributed with a mean of 58 dollars and a standard deviation of 5 dollars. What proportio
Airida [17]

Answer: 0.6267

Step-by-step explanation:

6 0
3 years ago
The rates of on-time flights for commercial jets are continuously tracked by the U.S. Department of Transportation. Recently, So
tatyana61 [14]

Answer:

The probability that at least 13 flights arrive late is 2.5196 \times 10^{-6}.

Step-by-step explanation:

We are given that Southwest Air had the best rate with 80 % of its flights arriving on time.

A test is conducted by randomly selecting 18 Southwest flights and observing whether they arrive on time.

The above situation can be represented through binomial distribution;

P(X = x) = \binom{n}{r}\times p^{r} \times (1-p)^{n-r} ; x = 0,1,2,3,.........

where, n = number of trials (samples) taken = 18 Southwest flights

           r = number of success = at least 13 flights arrive late

          p = probability of success which in our question is probability that

                flights arrive late, i.e. p = 1 - 0.80 = 20%

Let X = <u><em>Number of flights that arrive late</em></u>.

So, X ~ Binom(n = 18, p = 0.20)

Now, the probability that at least 13 flights arrive late is given by = P(X \geq 13)

P(X \geq 13) = P(X = 13) + P(X = 14) + P(X = 15) + P(X = 16) + P(X = 17) + P(X = 18)

= \binom{18}{13}\times 0.20^{13} \times (1-0.20)^{18-13}+ \binom{18}{14}\times 0.20^{14} \times (1-0.20)^{18-14}+ \binom{18}{15}\times 0.20^{15} \times (1-0.20)^{18-15}+ \binom{18}{16}\times 0.20^{16} \times (1-0.20)^{18-16}+ \binom{18}{17}\times 0.20^{17} \times (1-0.20)^{18-17}+ \binom{18}{18}\times 0.20^{18} \times (1-0.20)^{18-18}

= \binom{18}{13}\times 0.20^{13} \times 0.80^{5}+ \binom{18}{14}\times 0.20^{14} \times 0.80^{4}+ \binom{18}{15}\times 0.20^{15} \times 0.80^{3}+ \binom{18}{16}\times 0.20^{16} \times 0.80^{2}+ \binom{18}{17}\times 0.20^{17} \times 0.80^{1}+ \binom{18}{18}\times 0.20^{18} \times 0.80^{0}

= 2.5196 \times 10^{-6}.

7 0
3 years ago
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