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podryga [215]
3 years ago
5

if it is p miles from home to school how many round trips can be made if your car gets q miles per gallon of gasoline and there

are 5 gallons of gas in its tank
Mathematics
1 answer:
Bumek [7]3 years ago
3 0
5 is less than or equal to (2q)/p
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Function P is defined as P (x) = x ^2 . Explain why P (2) + P (3) isn't equal to P (5) .
diamong [38]

Answer:

P(x) = x + 2

Piden: A = P(P(P(P(3))))

P(3); x = 3

P(3) = 3 + 2 = 5

A = P(P(P(P(3))))

A = P(P(P(5)))

P(5); x = 5

P(5) = 5 + 2 = 7

A = P(P(P(5)))

A = P(P(7))

P(7); x = 7

P(7) = 7 + 2 = 9

A = P(P(7))

A = P(9)

P(9); x = 9

P(9) = 9 + 2 = 11

→ A = P(P(P(P(3)))) = 11

Step-by-step explanation:

listo e

4 0
3 years ago
0.2x + 0.3y = 0.5 need help plzz​
krok68 [10]

Answer:

y = − 0.  6 x + 1.6

Step-by-step explanation:

Write in slope-intercept form,  

y = m x + b

Note:

  • The decimals (0.6) and (1.6) ARE repeating...

If you need any other form of working it out let me know!

Glad I could help!!

6 0
3 years ago
Percentage:
masha68 [24]
20 percent
If you cross multiply 30 w/ 100 and then divide it by 150 you will get 20.
5 0
2 years ago
A landscape architect wished to enclose a rectangular garden on one side by a brick wall costing $20/ft and on the other three s
makvit [3.9K]

Answer:

The dimensions of the garden that minimize the cost is 9.018 feet(length) and 13.528 feet(width)

Step-by-step explanation:

Let the length of garden be x

Let the breadth of garden be y

Area of Rectangular garden = Length \times Breadth = xy

We are given that the area of the garden is 122 square feet

So, xy=122 ---A

A landscape architect wished to enclose a rectangular garden on one side by a brick wall costing $20/ft

So, cost of brick along length x = 20 x

On the other three sides by a metal fence costing $10/ft.

So, Other three side s = x+2y

So, cost of brick along the other three sides= 10(x+2y)

So, Total cost = 20x+10(x+2y)=20x+10x+20y=30x+20y

Total cost = 30x+20y

Substitute the value of y from A

Total cost = 30x+20(\frac{122}{x})

Total cost = \frac{2440}{x}+30x

Now take the derivative to minimize the cost

f(x)=\frac{2440}{x}+30x

f'(x)=-\frac{2440}{x^2}+30

Equate it equal to 0

0=-\frac{2440}{x^2}+30

\frac{2440}{x^2}=30

\sqrt{\frac{2440}{30}}=x

9.018 =x

Now check whether it is minimum or not

take second derivative

f'(x)=-\frac{2440}{x^2}+30

f''(x)=-(-2)\frac{2440}{x^3}

Substitute the value of x

f''(x)=-(-2)\frac{2440}{(9.018)^3}

f''(x)=6.6540

Since it is positive ,So the x is minimum

Now find y

Substitute the value of x in A

(9.018)y=122

y=\frac{122}{9.018}

y=13.528

Hence the dimensions of the garden that minimize the cost is 9.018 feet(length) and 13.528 feet(width)

4 0
3 years ago
A new company is purchasing a copier for their office. The table shows the costs associated with each copier. Write a system of
e-lub [12.9K]
Copier A:y=700x+0.02
Copier B:y=600x+0.06
8 0
3 years ago
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