Question

Can someone help me with 9, 10, & 11

Answer 1

Answer:

1) For, m =  3/4 ,  (0,4)  , 4y - 16 - 3x = 0  is the equation of line.

2) For, m =  4 ,  (-2,-5)  , y -  4x - 4  = 0  is the equation of line.

3) For, m =  -1/3 ,  (4,-1)  , x + 3y -1  = 0  is the equation of line.

Step-by-step explanation:

If m is the slope and (x0,y0) is the point on any given equation, then

by POINT SLOPE FORMULA:

The line equation is given as (y - y0) = m (x -x0)

Now , here:

1) m =  3/4 , (x0, y0) = (0.4)

So,, the equation of line is $(y-4) = \frac{3}{4} (x-0)\\or, 4(y-4) = 3x$

on simplification,  4y - 16 - 3x = 0  is the equation of line.

2) m =  4 , (x0, y0) = (-2.-5)

So,, the equation of line is $(y-(-5)) = 4 \times (x-(-2))\\or, (y+4) = 4(x+2)$

on simplification, y -  4x - 4  = 0  is the equation of line.

3) m =  -1/3 , (x0, y0) = (4, -1)

So,, the equation of line is $(y-(-1)) = \frac{-1}{3} (x-4)\\or, 3(y+1) = -(x-4)$

on simplification,   x + 3y -1  = 0  is the equation of line.