Answer:
Every day, there is a 49% percent the locust population.
Step-by-step explanation:
To find the daily percent change of the locust population, we just need to find N(t) for t = 0, N(t) for t = 1, then subtract the second by the first, and then divide the result by the first:
N(t) = 8950*(0.7)^2t
N(0) = 8950*(0.7)^0 = 8950*1 = 8950
N(1) = 8950*(0.7)^2 = 8950*0.49 = 4385.5
Change = N(1) - N(0) = 4564.5
Percent change = Change/N(0) = 4564.5/8950 = 0.51 = 51%
As after one day, the population decrease by 51% of the inicial population, the remaining population is 100% - 51% = 49%, so we can write:
Every day, there is a 49% percent of the locust population.
