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3 years ago

14

What equation do you obtain when you solve the formula A = 1/2bh for h?ASAP PLEASE

1 answer:

Katen [24]3 years ago

8 0

Answer:

2Ab=h

Step-by-step explanation:

A=1/2bh

2A=bh

2Ab=h

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Name two points on the line y = 6x. Does it describe a<br> proportional relationship?

tatuchka [14]

Answer:

b. Non-proportional

Step-by-step explanation:

A table of values that represents a proportional relationship will have the same ratio of every pair in the given table. That is, y/x will result in the same value all through for every given pair.

The table of values given does not show a proportional relationship, because the ratio of y to x of each given pair of values are different and unequal:

y/x = 3/1 ≠ 5/2 ≠ 7/3 ≠ 9/4

Therefore, it is non-proportional.

hope i help

8 0

3 years ago

Write the equation of the line passing through the point (2,-1) with a slope of -3

Alexxandr [17]

Y= 2x-3 i think, but i may be wrong

4 0

3 years ago

Read 2 more answers

Which line is perpendicular to the<br>line -x+ y=2?

mr Goodwill [35]

Answer:

y= -x+b

Step-by-step explanation:

hello :

the slope for the line : - x+y=2 is 1 because -x+y = 2 means y= 1x+2

all lines perpendicular to the line -x+y=2 have equation : y = ax+b

when : a×(1) = -1 so : a=-1

an equation is : y= -x+b

look the graph for the line : -x+y=2 (color red) and some lines

perpendicular to this line

5 0

3 years ago

Read 2 more answers

Suppose that .06 of each of two populations possess a given characteristic. Samples of size 400 are randomly drawn from each pop

omeli [17]

Answer:

The correct answer to the following question will be "0.0367".

Step-by-step explanation:

The given values are:

$p1=p2=0.06$

$q1=q2=1-p1=0.94$

$n1=n2=400$

As we know,

$E(p1-p2)=p1-p2=0\\$

$SE(p1-p2)=\sqrt{\frac{p1q1}{n1}+\frac{p2q2}{n2}}$

On putting the given values in the above expression, we get

$= \sqrt{p1q1(\frac{1}{400}+\frac{1}{400})}$

$=0.0168$

Now, consider

$P(p1-p2>0.03)=P[\frac{(p1-p2)-E(p1-p2)}{SE(p1-p2)}>\frac{0.03-0}{0.0168}]$

$=P(Z>1.7857)$

$=P(Z>1-79)$

$=0.036727$

Therefore, "0.0367" is the right answer.

8 0

3 years ago

The ratio of the lengths of an ellipse is 3:2. If it’s area is 150 cm2, what are the lengths of The major and minor semiaxes res

miv72 [106K]

Answer:

the length of major semiaxes a = 8.45 cm and minor semiaxes b= 5.63 cm.

Step-by-step explanation:

Area of ellipse = π*a*b

Let major semiaxes = a and minor semiaxes = b

then a:b = 3:2

a/b = 3/2

=> a = 3/2 b

Putting in the value of formula

150 = π * (3/2)b * b

150 = 3.14 * 1.5b * b

150= 4.71 b^2

150/4.71 = b^2

=> b^2 = 31.8

b= 5.63

a = 3/2 * b

a = 1.5 * 5.63

a = 8.45

So, the length of major semiaxes a = 8.45 cm and minor semiaxes b= 5.63 cm.

3 0

3 years ago