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Kruka [31]
4 years ago
11

For every for female students in a training class there are two men what is the ratio of female to male students

Mathematics
1 answer:
Katyanochek1 [597]4 years ago
5 0

For every for female students in a training class there are two men what is the ratio of female to male students.

Answer:

1:2

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PLEASE HELP SOLVE THIS GRAPH
LUCKY_DIMON [66]

Answer:

I'm pretty sure that is the correct answer

Step-by-step explanation:

3 0
3 years ago
Let ​ f(x)=x2−6x−27 ​ . Enter the x-intercepts of the quadratic function in the boxes. x = and x =
Akimi4 [234]

Answer:

-3, 9

Step-by-step explanation:

x^2 -6x - 27=

= x^2 - 9x + 3x - 27

= x(x - 9) + 3(x - 9)

= (x + 3)(x - 9)

x = -3, x = 9

8 0
4 years ago
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2. Suppose that you are looking for a student at your college who lives within five miles of you. You know that 55% of the 25,00
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6 0
3 years ago
In fraction 5_8, what is the tem used to designate the 5?
Ierofanga [76]

Answer:

Numerator = 5

Step-by-step explanation:

A fraction is in the form of \dfrac{x}{y}.

x is numerator of the fraction and y is the denominator.

The given fraction is \dfrac{5}{8}.

Here,

5 is the numerator and 8 is the denominator.

Hence, in the given fraction, 5 is the numerator and 8 denotes the denominator.

5 0
3 years ago
The woodson and baker families went to the burger shack for dinner. The Woodsons bought 3 burger meals and 4 hot dog meals for $
Klio2033 [76]

Answer:

Burger meal costs $8 and hot dog meal costs $6.

Step-by-step explanation:

To find the price per meal, write a system of equations.

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Write the equation 3b + 4d = 48 for the Woodsons.

Write the equation 6b + 2d = 60 for the Barkers.

Use elimination to solve the system. Begin by making the coefficients of one variable the same in both equations by multiplying 3b + 4d = 48 by 2.

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Stack the equations and subtract.

   6b + 8d = 96

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------------------------

            6d = 36

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Substitute d = 6 into one equation to solve for b.

3b + 4(6) = 48

3b + 24 = 48

3b = 24

b = 8

7 0
4 years ago
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