A pyramid with a square base of length 3 cm and height 16 cm

Mathematics

1 answer:

GuDViN [60]3 years ago

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A Ferrari can travel up to 217 miles per hour. How many feet per second is this equivalent to?

kari74 [83]

Answer:

318.267 feet per second

19096 feet per minute

Step-by-step explanation:

1) 217*5280 to get feet

2) 1145760/60 to get feet per minute

3) 19096/60 to get feet per second

7 0

3 years ago

Read 2 more answers

Frank bought 18 water bottles and 28 candy bars for a reunion. Water bottle cost 1.80 for a six pack. Candy bars cost 4.20 for 6

iogann1982 [59]

Answer:

$17.60

Step-by-step explanation:

Let’s start by first finding the cost of 1 candy bar. We have to divide 1.80 by 6 to find the cost of 1 water bottle and 4.20 divided by 6 to find the cost of 1 candy bar. 1 water bottle= 30 cents (0.3) and 1 candy bar= 70 cents (0.7). Now, to find how much he spent on 18 water bottles we must multiply 18 by 0.3 which = $60 and multiply 28 by 0.7 = $19.60 (19.6). Now add 19.60 + 60 = 79.60 (79.6)

So, Frank spent $79.60 on food total. Sorry if I got it wrong, but hope this helps!

6 0

3 years ago

Verify cot x sec^4x=cotx +2tanx +tan^3x

Tanzania [10]

Answer:

See explanation

Step-by-step explanation:

We want to verify that:

$\cot(x) \: { \sec}^{4} x = \cot(x) + 2 \tan(x) + { \tan}^{3} x$

Verifying from left, we have

$\cot(x) \: { \sec}^{4} x = \cot(x) \: ( 1 + { \tan}^{2} x )^{2}$

Expand the perfect square in the right:

$\cot(x) \: { \sec}^{4} x = \cot(x) \: ( 1 + { 2\tan}^{2} x + { \tan}^{4} x)$

We expand to get:

$\cot(x) \: { \sec}^{4} x = \cot(x) \: + \cot(x){ 2\tan}^{2} x +\cot(x) { \tan}^{4} x$

We simplify to get:

$\cot(x) \: { \sec}^{4} x = \cot(x) \: + 2 \frac{ \cos(x) }{\sin(x) ) } \times \frac{{ \sin}^{2} x}{{ \cos}^{2} x} +\frac{ \cos(x) }{\sin(x) ) } \times \frac{{ \sin}^{4} x}{{ \cos}^{4} x}$