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tatyana61 [14]
3 years ago
7

In a race of 35 people, how many different ways can we have a 1st, 2nd and 3rd place finisher?

Mathematics
1 answer:
kumpel [21]3 years ago
8 0

Answer:

39,270 ways.

Step-by-step explanation:

That is the number of permutations of 3 from 35.

35P3 = 35! / (35-3)!

= 35*34*33

= 39270.

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At a grocery store I bought a bag of 7 apples. Some apples are red and some apples are green. How many combination of 7 apples c
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3 years ago
Anna is a teacher at an elementary school. She purchased 73 tickets to take the first-grade children and some parents on a field
Svetllana [295]

She bought 54 child tickets and 19 adult tickets.

Step-by-step explanation:

No. of tickets purchased = 73

Cost of tickets = $771

Cost of one child ticket = $9

Cost of one adult ticket = $15

Let,

Child ticket = x

Adult ticket = y

According to given statement;

x+y=73   Eqn 1

9x+15y=771   Eqn 2

Multiplying Eqn 1 by 9;

9(x+y=73)\\9x+9y=657\ \ \ Eqn\ 3\\

Subtracting Eqn 3 from Eqn 2;

(9x+15y)-(9x+9y)=771-657\\9x+15y-9x-9y=114\\6y=114\\

Dividing both sides by 6;

\frac{6y}{6}=\frac{114}{6}\\y=19

Putting y=19 in Eqn 1

x+19=73\\x=73-19\\x=54\\

She bought 54 child tickets and 19 adult tickets.

Keywords: linear equations, subtraction

Learn more about linear equations at:

  • brainly.com/question/3227215
  • brainly.com/question/3269852

#LearnwithBrainly

4 0
3 years ago
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Rewrite In simplest radical form x^5/6/x^1/6
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I assume you mean:

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x^(5/6-1/6)

x^(4/6)

x^(2/3)
3 0
3 years ago
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