2 years ago

Determine the number of real solutions of -2x2 + 5x - 3 = 0.

Mathematics

1 answer:

andrew11 [14]2 years ago

4 0

-2x^2 + 5x -3 =0

Find the discriminate:

In the given formula a = -2, b = 5 and c = -3

The discriminate is found using the formula b^2 - 4(ac)

Replace the letters with their values:

5^2 - 4(-2*-3)

25 - 4*6

25-24 = 1

When the discriminate is greater than or equal to 0, there are two real solutions.

The answer is c) 2

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I solved some of it but now I don't know if you continue it correctly ... To be performed: (lesson: Raducali of order "n")

nikitadnepr [17]

Answer:

-9

Step-by-step explanation:

$( \sqrt[4]{7} + 2)( \sqrt[4]{7} - 2)( \sqrt{7} + 4) \\ = ( { \sqrt[4]{7} }^{2} - {{2} }^{2} )( \sqrt{7} + 4) [because (a+b)(a-b) = a² - b²]\\ = ( \sqrt{7} - 4)( \sqrt{7} + 4) \\ = { \sqrt{7} }^{2} - {4}^{2}[because (a+b)(a-b) = a² - b²] \\ = 7 - 16 \\ = - 9$