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aivan3 [116]
3 years ago
5

Which statement is not true about histograms

Mathematics
1 answer:
Eduardwww [97]3 years ago
8 0

Answer:

d

Step-by-step explanation:

d is not true because width and thickness doesn't matter

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Carefully review the research matrix presented below. If this is a within subjects design, how many total participants will be u
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Answer:

c. 45

Step-by-step explanation:

there are 15 participant in each category, and there are 3 categories, so total participants = 15 * 3

= 45

Hope this helps, and please mark me brainliest if it does!

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3 years ago
(02.01MC)The Department of Health in the Germany wants to know whether the national healthcare system is achieving its goals in
solniwko [45]

It should be noted that a population means the entire group that a researcher wants to draw conclusions about.

<h3>What is a population?</h3>

Your information is incomplete s the data is not provided. Therefore, an overview will be given.

In statistics, a population refers to a set of similar items which is of interest for an experiment.

On the other hand, a sample is a set of individuals or objects that are selected from a statistical population through a defined procedure.

In this case, it is important to deduce if the sample represents the population.

Learn more about population on:

brainly.com/question/25896797

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1 year ago
The ages of the students in a dance class are 10, 9, 11, 12, 9, 10, 9, 10, 11, 12, 8, 12, 12.
faust18 [17]

Answer:

Put the numbers in order then find the number that appears the most which is 12.

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Integration of ∫(cos3x+3sinx)dx ​
Murljashka [212]

Answer:

\boxed{\pink{\tt I =  \dfrac{1}{3}sin(3x)  - 3cos(x) + C}}

Step-by-step explanation:

We need to integrate the given expression. Let I be the answer .

\implies\displaystyle\sf I = \int (cos(3x) + 3sin(x) )dx \\\\\implies\displaystyle I = \int cos(3x) + \int sin(x)\  dx

  • Let u = 3x , then du = 3dx . Henceforth 1/3 du = dx .
  • Now , Rewrite using du and u .

\implies\displaystyle\sf I = \int cos\ u \dfrac{1}{3}du + \int 3sin \ x \ dx \\\\\implies\displaystyle \sf I = \int \dfrac{cos\ u}{3} du + \int 3sin\ x \ dx \\\\\implies\displaystyle\sf I = \dfrac{1}{3}\int \dfrac{cos(u)}{3} + \int 3sin(x) dx \\\\\implies\displaystyle\sf I = \dfrac{1}{3} sin(u) + C +\int 3sin(x) dx \\\\\implies\displaystyle \sf I = \dfrac{1}{3}sin(u) + C + 3\int sin(x) \ dx \\\\\implies\displaystyle\sf I =  \dfrac{1}{3}sin(u) + C + 3(-cos(x)+C) \\\\\implies \underset{\blue{\sf Required\ Answer }}{\underbrace{\boxed{\boxed{\displaystyle\red{\sf I =  \dfrac{1}{3}sin(3x)  - 3cos(x) + C }}}}}

6 0
3 years ago
Psl help simplify this
Luba_88 [7]

Answer:

See the image below:)

Step-by-step explanation:

6 0
2 years ago
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