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Vilka [71]
2 years ago
10

Which of the following inequalities is best represented by this graph?

Mathematics
2 answers:
romanna [79]2 years ago
8 0

Answer: x-2y > 3

Step-by-step explanation:

By the given diagram,

The related line of the inequality is passes through the point (0,-1.5) and (3,0)

Thus, the equation of the related line,

y-(-1.5)=\frac{0-(-1.5)}{(3-0)} (x-0)

y+1.5=\frac{(0+1.5)}{3}x

y+1.5=\frac{1.5}{3}x

y+\frac{15}{10}=\frac{15}{30}x

y+\frac{3}{2}=\frac{1}{2}x

\frac{2y+3}{2}=\frac{1}{2}x

2y+3=x\implies 2y+3-x=0\implies -x+2y=-3\implies x-2y=3

Thus, the related line of the given inequality is x-2y=3

Hence, the possible inequalities are,

x-2y ≥ 3, x-2y ≤ 3, x-2y > 3 or x-2y < 3

By the given diagram,

The inequality does not contains the origin,

Thus, the possible inequalities are x-2y ≥ 3 or x-2y > 3.

Again,

The doted line shows that the inequality does not contain the equal sign.

Hence, the inequality is,

x-2y > 3

⇒ First option is correct.

blondinia [14]2 years ago
7 0
Based on the graph we see that the slope is 1/2

By simplifying each of these expressions, that leaves on options 1 and 2 that fit this.

Since the shaded area is going downward, the choice including less than is what's pictured.

Choice One is the correct answer
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1. Write the equation in standard form. Identify the important features of the graph:
NeTakaya

Answer:

  1. (x-4.5)^2 +(y +5)^2 = 30.25
  2. x = (1/8)y^2 +(1/2)y +(1/2)
  3. y^2/36 -x^2/64 = 1
  4. x^2/16 +y^2/25 = 1

Step-by-step explanation:

1. Complete the square for both x and y by adding a constant equal to the square of half the linear term coefficient. Subtract 15, and rearrange to standard form.

  (x^2 -9x +4.5^2) +(y^2 +10y +5^2) = 4.5^2 +5^2 -15

  (x -4.5)^2 +(y +5)^2 = 30.25 . . . . . write in standard form

Important features: center = (4.5, -5); radius = 5.5.

__

2. To put this in the form x=f(y), we need to add 8x, then divide by 8.

  x = (1/8)y^2 +(1/2)y +(1/2)

Important features: vertex = (0, -2); focus = (2, -2); horizontal compression factor = 1/8.

__

3. We want y^2/a^2 -x^2/b^2 = 1 with a=36 and b=(36/(3/4)^2) = 64:

  y^2/36 -x^2/64 = 1

__

4. In the form below, "a" is the semi-axis in the x-direction. Here, that is 8/2 = 4. "b" is the semi-axis in the y-direction, which is 5 in this case. We want x^2/a^2 +y^2/b^2 = 1 with a=4 and b=5.

  x^2/16 +b^2/25 = 1

_____

The first attachment shows the circle and parabola; the second shows the hyperbola and ellipse.

6 0
2 years ago
Consider ΔWXY and ΔBCD with ∠X ≅∠C, WX ≅ BC, and WY ≅ BD.
LenKa [72]

Answer:- B. No, because the corresponding congruent angles listed are not the included angles.


Explanation:-

Given:- ΔWXY and ΔBCD with ∠X ≅∠C, WX ≅ BC, and WY ≅ BD.

Now, look at the attachment

We can see that ∠X and ∠C are not included angles by the corresponding equal sides.

⇒ We cannot use SAS postulate to show ΔWXY ≅ ΔBCD .

⇒ B is the right option.

SAS postulate tells the if two sides of a triangle and their included angle is equal to the two sides of a triangle and their included angle of another triangle then the two triangles are congruent.

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3 years ago
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ON the blue cube there are 4 numbers greater than 2 and on the blue cube, 3 of the numbers are odd. As soon as BOTH outcomes have to happen (AND), you multiply the probabilities.

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