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Diano4ka-milaya [45]
3 years ago
9

A circular patio has a diameter of 4 yards. What is the area of the patio? Use 3.14 for π.

Mathematics
2 answers:
My name is Ann [436]3 years ago
8 0

Answer:

50.24 square yards

Step-by-step explanation:

area = 3.14 × 4²

Mkey [24]3 years ago
8 0

Answer:

12.56 yd2

Step-by-step explanation:

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6 0
3 years ago
On a sunny day, a flag pole and its shadow form the sides of a right triangle. if the hypotenuse is 35 meters long and the shado
Triss [41]
We can use Pythagorean's Theorem in order to find the remaining side length
a^2+b^2=c^2
Let a be the shadow length
Let b be the height of the flagpole
Let c be the hypotenuse 
28^2+b^2=35^2
784+b^2=1225
b^2=1225-784
b^2=441
b=√441
b=21
Therefore the flagpole is 21 meters tall.
Hope this helps!
 
 
3 0
3 years ago
-10x = -210 how would i find this answer?
jeka94

To find the answer to -10x=-210 you must divide -210 by -10

-210/-10= 21

Therefore x=21

So the proper equation is -10(21)=-210

3 0
2 years ago
Read 2 more answers
Use 3.14 for the value of , and round your answers to two decimal places, where applicable. If the diameter of a circle is 15 m,
sergejj [24]

if the diameter of a circle is 15, its radius is half that or 7.5.

\bf \textit{area of a circle}\\\\ A=\pi r^2~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ r=7.5 \end{cases} A=\pi (7.5)^2\implies A=56.25\pi \implies \stackrel{\pi =3.14}{A=176.625}

7 0
2 years ago
ANSWER PLS URGENT VERY URGENT TYSM ik its a lot of questions but id really really be grateful for the help
anyanavicka [17]

Step-by-step explanation:

about circle R

arc angle MP = angle MRP = 78°

angle M = angle LMP.

according to the rules of inscribed angles, LMP is half of angle LRP.

LRP + MRP = 180° because together they cover the whole LM segment (half-circle).

LRP = 180 - MRP = 180 - 78 = 102°

so, LMP = angle M = 102/2 = 61°

also circle R (with arc ULNP)

the arc ULNP = arc UL + arc LN + arc NP = 160°

due to the congruent definition of JU and MP we know that arc UL = arc NP.

and we know arc LN = arc JM = 18°.

so,

160 = 2×arc NP + 18

142 = 2×arc NP

arc NP = 71° = arc UL

now, because arc MP + arc LP = 180 (half-circle),

arc MP = 180 - arc LP = 180 - arc LN - arc NP =

= 180 - 18 - 71 = 91°

about the circle R with 2 congruent chords :

the second answer : they are equidistant from R (the center of the circle).

about circle W

arc MK + arc KL = 180° (half-circle).

and we see

arc HL = arc KL = 53°.

so,

arc MK + 53 = 180°

arc MK = 180 - 53 = 127°

about circle M

arc QTS = 204°.

therefore, arc QRS = 360 - arc QTS = 360 - 204 =

= 156° = angle QMS.

according to the rules of inscribed angles

angle QTS = QMS/2 = 156/2 = 78°

4 0
2 years ago
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